Compute its design strength based on rupture in kiloNewtons..* 412 485 453 389 438 This is a required question A steel beam section is use as a tension member, with 8- 16 mm bolts are used at each flanges to attach to another member. Assume diameter of the hole is 2 mm larger than the bolt diameter. Fu = 400 MPa, Fy = 248 MPa Using NSCP 2015 Properties of steel section: WF Section A=2284 mm² tf-5.33 mm tw = 4.83 mm bf=100.58 mm d=250.70 mm T I Equivalent WT y = 34.54 mm H 75-75-75-50

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Author:Segui, William T.
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Chapter5: Beams
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Compute its design strength based on rupture in kiloNewtons..
412
485
453
389
438
This is a required question
A steel beam section is use as a tension member, with 8- 16 mmØ bolts
are used at each flanges to attach to another member. Assume diameter
of the hole is 2 mm larger than the bolt diameter. Fu = 400 MPa, Fy = 248
MPa
Using NSCP 2015
Properties of steel section:
WF Section
A = 2284 mm²
tf = 5.33 mm
f
tw = 4.83 mm
bf 100.58 mm
d=250.70 mm
Equivalent WT
y = 34.54 mm
T
75--75-75-50
Ö
110
Transcribed Image Text:Compute its design strength based on rupture in kiloNewtons.. 412 485 453 389 438 This is a required question A steel beam section is use as a tension member, with 8- 16 mmØ bolts are used at each flanges to attach to another member. Assume diameter of the hole is 2 mm larger than the bolt diameter. Fu = 400 MPa, Fy = 248 MPa Using NSCP 2015 Properties of steel section: WF Section A = 2284 mm² tf = 5.33 mm f tw = 4.83 mm bf 100.58 mm d=250.70 mm Equivalent WT y = 34.54 mm T 75--75-75-50 Ö 110
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