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Can you calculate percent and theoretical yield? Final Eugenol mass: 127.13g - 126.2g = 0.93g Eugerol CHO carbon 12.011 x 10 = 120.01 Hydrogen 1.0078 x 12 = 12.0936 = 164.1016= Molar mass of 10 12 2 Eugenol oxygen 15.999 x 2 = 31.998 moks of Eugerol = 0.00566722 p 0.93 0.93 = 0.00566722 + 10.0g = 0.0851 164.1016 0.93

Can you calculate percent and theoretical yield? Final Eugenol mass: 127.13g - 126.2g = 0.93g Eugerol CHO carbon 12.011 x 10 = 120.01 Hydrogen 1.0078 x 12 = 12.0936 = 164.1016= Molar mass of 10 12 2 Eugenol oxygen 15.999 x 2 = 31.998 moks of Eugerol = 0.00566722 p 0.93 0.93 = 0.00566722 + 10.0g = 0.0851 164.1016 0.93

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter4: Stoichiometry Of Chemical Reactions
Section: Chapter Questions
Problem 65E: Freon-12, CCl2F2, is prepared from CCl4 by reaction with HF. The other product of this reaction is...
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question → Can you calculate percent and theoretical yield? Final Eugenol mass: 127.13g - 126.2g = 0.93g Eugerol CHO carbon 12.011 x 10 = 120.01 Hydrogen 1.0078 x 12 = 12.0936 = 164.1016= Molar mass of 10 12 2 Eugenol oxygen 15.999 x 2 = 31.998 moks of Eugerol = 0.00566722 p 0.93 0.93 164.1016 = 0.00566722 + 10.0g = 0.0851 0.93 G
Transcribed Image Text:question → Can you calculate percent and theoretical yield? Final Eugenol mass: 127.13g - 126.2g = 0.93g Eugerol CHO carbon 12.011 x 10 = 120.01 Hydrogen 1.0078 x 12 = 12.0936 = 164.1016= Molar mass of 10 12 2 Eugenol oxygen 15.999 x 2 = 31.998 moks of Eugerol = 0.00566722 p 0.93 0.93 164.1016 = 0.00566722 + 10.0g = 0.0851 0.93 G
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