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Calculation of vinegar Sample Volume of diluted vinegar 28.5 mL 2.1 M 47 mL Molar Concentration of NaOH Titration volume of NaOH % acetic acid in vinegar 22.60% End point From graph: 55mL FW acetic acid 60.052

Calculation of vinegar Sample Volume of diluted vinegar 28.5 mL 2.1 M 47 mL Molar Concentration of NaOH Titration volume of NaOH % acetic acid in vinegar 22.60% End point From graph: 55mL FW acetic acid 60.052

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter16: Reaction Rates
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Are my equivalence point calculations correct? I got a different Veq than the end point on my graph. 

Calculation of Percent Acetic Acid in Vinegar Sample Volume of diluted vinegar 28.5 mL 2.1 M 47 mL Molar Concentration of NaOH Titration volume of NaOH % acetic acid in vinegar 22.60% End point From graph: 55mL FW acetic acid 60.052
Transcribed Image Text:Calculation of Percent Acetic Acid in Vinegar Sample Volume of diluted vinegar 28.5 mL 2.1 M 47 mL Molar Concentration of NaOH Titration volume of NaOH % acetic acid in vinegar 22.60% End point From graph: 55mL FW acetic acid 60.052
@ Veq moles NaOH = males of acetic acids 106-1 0.05.56 (2.1 Mot 1L 3.5mal •115. moles (3 NaOH = .115 males sedir resid 20.0329 = Veq is 32.9ML (28 m²) (M) x (2.1 M) (47mL) = 3.5 mol acetic acid
Transcribed Image Text:@ Veq moles NaOH = males of acetic acids 106-1 0.05.56 (2.1 Mot 1L 3.5mal •115. moles (3 NaOH = .115 males sedir resid 20.0329 = Veq is 32.9ML (28 m²) (M) x (2.1 M) (47mL) = 3.5 mol acetic acid
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