(Calculation) If your unknown solution is first diluted 11 times and then a30ml aliquot is taken and diluted in a 50.00ml volumetric flask, what is theoverall dilution factor?Note the values used in this question may differ from those used in theexperiment. However, you will need to be able to perform calculations ofthis type in the experiment.18.33Show in steps how to get this answear

Given: Unknown solution is diluted 11times then 30 mL aliquot is diluted to 50mL volume.

Answered: (Calculation) If your unknown solution…

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter16: Solutions

Section: Chapter Questions

Problem 100E: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a...

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Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the formula KHC8H4O4. This is often written in the short-hand notation as KHP. If 25.0mL of a potassium hydroxide solution are needed to neutralize 2.26g of KHP, what is the molarity of the potassium hydroxide solution? Potassium hydrogen phthalate sometimes called potassium biphthalate, as shown on this bottle is an acid that is convenient to store and use because it is a solid.
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Hi, My question was not completed at first, let me rephrase my question. The experiment in the lab was part of accurately weigh out about 0.17 to 0.20g naphthalene to 0.001g in a weighing paper. Quantitatively transfer thenaphthalene to your t-butanoland stir the mixture until a naphthalene dissolves. Question: How would the freezing point of the solution be affected if all the naphthalene were not transferred?
given the molar mass of of compound A as 327.34g/mol and the mass being 0.016g. calculate the concentration of compound A (the stock standard) if it is mixed with 50ml water then 2ml, 4ml and 6ml of the stock standard are measured into a 10ml volumetric flask. calculate the concentrations of the 2ml, 4ml and 6 ml solutions.
Five drops of dichlorofluorescein have been added to a solution containing 0.800 g sample which required 25.30 mL of 0.100 M AgNO3. (c) Calculate the weight percent NaCl in the original sample.
[attached is the given data] Questions: What is the weight of sodium chloride (in grams) required to adjust the tonicity of the solution?
1. You are given a substance that is equally soluble in water and hexane (two immiscible solvents). a) What is K,? b) If you start with 10 g of the substance dissolved in 100 ml of water and are given 100 ml of hexane to extract with, algebraically show that it is better to do two smaller extractions using 50 ml of hexane for each extraction than it is to do one extraction using 100 ml of hexane.
If the same mass of Na2SO4 (MW: 142 g/mol) and K2SO4 (MW: 174 g/mol) were weighed and used for the gravimetry experiment, which will yield a greater amount of precipitate? Assume that the experiment was done correctly. Indeterminate, it will depend on the (A amount of BaCl2 used. Na „SO, , because it has a smaller В molecular weight. They will yield the same amount of precipitate because the same mass was initially weighed. K,SO, , because it has a larger (D molecular weight. 4
Consider the following scenario: After the first compound elutes off of the column, you collect multiple fractions without seeing the next compound begin to elute. What change might you want to make before you continue taking fractions?
d. All of these. 9. Concentration of the stock solution is 0.30m. Howmuch of it would have to be diluted to the totAl of 10:00ml to get the conc of O. 0005m? a) n ml b) 17 microL c)17 mol
Please don't provide handwritten solution solution .....
A. Standardlzatlon of thlosulfate solutlon Trial 1 Trial 2 Trial 3 Initial volume of thiosulfate (mL) 0.00 20.05 2.3 Final volume of thiosulfate (mL) 20.05 40.05 22.15 Volume of thiosulfate used (mL) Molarity of thiosulfate Average Molarity of thiosulfate Calculate the molarity of the thiosulfate solution using the formula: 6 mmol S20,²- 1 mmol 10, Ms,0,2- 0.004167 M 10,- 20.00 ml Vol S20,²- used (mL)

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