Calculate the standard enthalpy of formation of liquid methanol, CH3OH(1), using the following information: C(graph)+ O₂ → CO₂(g) AH° -393.5 kJ/mol H₂(g) + (1/2)02 → H₂O(1) AH° -285.8 kJ/mol CH3OH(1)+(3/2)O₂(g) → CO₂(g) + 2H₂O(1) AH°=-726.4 kJ/mol Multiple Choice -238.7 kJ/mol 1691.5 kJ/mol -47.1 kJ/mol 471 kJ/mol -1,691.5 kJ/mol

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 89GQ: Chloroform, CHCl3, is formed from methane and chlorine in the following reaction. CH4(g) + 3 Cl2(g) ...
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Q.98.

 

Calculate the standard enthalpy of formation of liquid methanol, CH3OH(1), using the
following information:
C(graph) + O2 → CO₂(g)
AH°
-393.5 kJ/mol
H₂(g) + (1/2)02 → H₂O(1)
AH° -285.8 kJ/mol
CH3OH(1)+(3/2)O2(g) → CO2(g) + 2H₂O(1) AH = -726.4 kJ/mol
Multiple Choice
O
-238.7 kJ/mol
1691.5 kJ/mol
-47.1 kJ/mol
471 kJ/mol
-1,691.5 kJ/mol
Transcribed Image Text:Calculate the standard enthalpy of formation of liquid methanol, CH3OH(1), using the following information: C(graph) + O2 → CO₂(g) AH° -393.5 kJ/mol H₂(g) + (1/2)02 → H₂O(1) AH° -285.8 kJ/mol CH3OH(1)+(3/2)O2(g) → CO2(g) + 2H₂O(1) AH = -726.4 kJ/mol Multiple Choice O -238.7 kJ/mol 1691.5 kJ/mol -47.1 kJ/mol 471 kJ/mol -1,691.5 kJ/mol
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