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Calculate the standard deviation for the molarity of ascorbic acid in the vitamin C supplement solution. What does your standard deviation tell you about the precision of your titration measurements?

Calculate the standard deviation for the molarity of ascorbic acid in the vitamin C supplement solution. What does your standard deviation tell you about the precision of your titration measurements?

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.102QE
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Calculate the standard deviation for the molarity of ascorbic acid in the vitamin C supplement solution.
What does your standard deviation tell you about the precision of your titration measurements? 

Chemistry 201 College of the Canyons nart 3. Titration of Unknown Ascorbic Acid Solution with NaOH Ascorbic Acid Content in Vitamin C Supplements The neutralization reaction between ascorbic acid and NaOH is: HC,H,06(aq) + NaOH(aq) NaC,H,06(aq) + H20(1) Data Table 3. Titration of an Ascorbic Acid Solution Trial 1 Volume of ascorbic acid Trial 2 Trial 3 solution, mL 25.00mL 25.00mL 25.00ML NaOH buret reading before titration, mL 6.38 mL 10.02 mL 13.94ML NaOH buret reading 10.02 mL after titration, mL 13.94 mL 17.76 mL Volume of NaOH solution added, mL 3.64 mL 3.92 mL 3.82mL Mole of NaOH 1.038x 10moi 1.118x10mol 1. 090x 10 mol Concentration of 0.04152M 0.04472M 0.0436M ascorbic acid, M Average ascorbic acid concentration, M 0.04328 M (Show work here) Average concentrahon of Naott = 0,2853M 0.2853 mol NADH x 0.00364K = 1.038x10 mol NaoH Trial 1:nE 1.038x103 mol Asconbic acid = 0.OHI52 M 0,025 L Trial 2: n= 0.2853 moI NAOH J.118X10 mol Accorbic acid x 0.00392L = 1.118x1073 mol NaOH 0.04H12 M %3D 0.025L 0. 2853 mol NaOH x0.00382 L= 1.090 x 103 mol NaOH Trial 3:.2 1.090 x10mol NAOH 10.0436 M 0.025L 64
Transcribed Image Text:Chemistry 201 College of the Canyons nart 3. Titration of Unknown Ascorbic Acid Solution with NaOH Ascorbic Acid Content in Vitamin C Supplements The neutralization reaction between ascorbic acid and NaOH is: HC,H,06(aq) + NaOH(aq) NaC,H,06(aq) + H20(1) Data Table 3. Titration of an Ascorbic Acid Solution Trial 1 Volume of ascorbic acid Trial 2 Trial 3 solution, mL 25.00mL 25.00mL 25.00ML NaOH buret reading before titration, mL 6.38 mL 10.02 mL 13.94ML NaOH buret reading 10.02 mL after titration, mL 13.94 mL 17.76 mL Volume of NaOH solution added, mL 3.64 mL 3.92 mL 3.82mL Mole of NaOH 1.038x 10moi 1.118x10mol 1. 090x 10 mol Concentration of 0.04152M 0.04472M 0.0436M ascorbic acid, M Average ascorbic acid concentration, M 0.04328 M (Show work here) Average concentrahon of Naott = 0,2853M 0.2853 mol NADH x 0.00364K = 1.038x10 mol NaoH Trial 1:nE 1.038x103 mol Asconbic acid = 0.OHI52 M 0,025 L Trial 2: n= 0.2853 moI NAOH J.118X10 mol Accorbic acid x 0.00392L = 1.118x1073 mol NaOH 0.04H12 M %3D 0.025L 0. 2853 mol NaOH x0.00382 L= 1.090 x 103 mol NaOH Trial 3:.2 1.090 x10mol NAOH 10.0436 M 0.025L 64
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