4.Calculate the grams of analyte per gram of precipitate for the following conversions:Supstance weighedB203 (69.64)(NH4)3PO4 12 MoO3 (1876.38)M92P20, (222.57)Substance soughtNa2B407= 10H20 (381.44)P2Os (141.95)P (30.97)

We need to calculate the grams of analyte per gram of precipitate, ie. the gravimetric factor.

Calculate the grams of analyte per gram of precipitate for the following conversions: Supstance weighed B2O3 (69.64) (NH4)3PO4 12 MoO3 (1876.38) Mg:P207 (222.57) Substance sought NazB.O7= 10H20 (381.44) P2Os (141.95) P (30.97)

Calculate the grams of analyte per gram of precipitate for the following conversions: Supstance weighed B2O3 (69.64) (NH4)3PO4 12 MoO3 (1876.38) Mg:P207 (222.57) Substance sought NazB.O7= 10H20 (381.44) P2Os (141.95) P (30.97)

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter4: Stoichiometry

Section: Chapter Questions

Problem 4.87PAE

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

4.
Calculate the grams of analyte per gram of precipitate for the following conversions:
Supstance weighed
B203 (69.64)
(NH4)3PO4 12 MoO3 (1876.38)
M92P20, (222.57)
Substance sought
Na2B407= 10H20 (381.44)
P2Os (141.95)
P (30.97)

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