Calculate Eºcell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. H2O2 (aq) + 2 H +1 Fe +3 (aq) +e-1: Overall reaction: +3 2Fe (aq) + 2 e- -1 ⇒ Fe +² (aq); E O = 0.77 V +2 (aq) + 2 H2O () Ź 2Fe 2 H₂O (1); E0 = 1.77 V +2 (aq) + 2 H+1 (aq) + H₂O2 (aq)

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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.127QP
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Calculate Eº cell and indicate whether the overall reaction shown is
spontaneous or nonspontaneous.
H2O2 (aq) + 2 H +1
Fe +3
Overall reaction:
O
2Fe
E
(aq)
B
C
A
(aq) + 2 e
+3
+ e -1 ⇒ Fe +² (aq); E O = 0.77 V
-1
(aq) + 2 H2O ()
a) Eºcell = -1.00 V, nonspontaneous
b) Eᵒcell = -1.00 V, spontaneous
c) Eºcell = 1.00 V, nonspontaneous
d) Eºcell =
1.00 V, spontaneous
e) Eºcell = -0.23 V, nonspontaneous
Ź 2Fe
2 H₂O (1); E0 = 1.77 V
+2
(aq) + 2 H+1
(aq) + H₂O2 (aq)
Transcribed Image Text:Calculate Eº cell and indicate whether the overall reaction shown is spontaneous or nonspontaneous. H2O2 (aq) + 2 H +1 Fe +3 Overall reaction: O 2Fe E (aq) B C A (aq) + 2 e +3 + e -1 ⇒ Fe +² (aq); E O = 0.77 V -1 (aq) + 2 H2O () a) Eºcell = -1.00 V, nonspontaneous b) Eᵒcell = -1.00 V, spontaneous c) Eºcell = 1.00 V, nonspontaneous d) Eºcell = 1.00 V, spontaneous e) Eºcell = -0.23 V, nonspontaneous Ź 2Fe 2 H₂O (1); E0 = 1.77 V +2 (aq) + 2 H+1 (aq) + H₂O2 (aq)
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