Calculate AG for the reaction given below if the partial pressure of NO2 is 0.229 atm and the partial pressure of N204 is 0.464 atm. 2NO2(g) N204(g) AG°298 of this reaction is -5.40kJ per mole of N,O. T= 298K, R = 8.314 J-mol 1.K-1 Note: Round you answer to 2 decimal places. AG= kJ mol-1 Where does the system stand relative to equilibrium? O The equilibrium shifts to products. O The system is at equilibrium, so that the reaction will not move. O The equilibrium shifts to reactants.

Calculate AG for the reaction given below if the partial pressure of NO2 is 0.229 atm and the partial pressure of N204 is 0.464 atm. 2NO2(g) N204(g) AG°298 of this reaction is -5.40kJ per mole of N,O. T= 298K, R = 8.314 J-mol 1.K-1 Note: Round you answer to 2 decimal places. AG= kJ mol-1 Where does the system stand relative to equilibrium? O The equilibrium shifts to products. O The system is at equilibrium, so that the reaction will not move. O The equilibrium shifts to reactants.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter17: Spontaneity, Entropy, And Free Energy

Section: Chapter Questions

Problem 121CP: If wet silver carbonate is dried in a stream of hot air. the air must have a certain concentration...

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