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- The nitrite in a series of standard solutions (mg/L, n = 5) are converted to azo dye and the slope of the calibration curve is 2.0 ppm1. A 10.00-mL mineral water sample is treated in the same way as standards and diluted to a final volume of 100.00-mL. It gives an absorbance of 0.80. The absorbance of blank solution under the same conditions is 0.10. Calculate ppm (mg/L) of NO2 (46 g/mol) and the molarity of NANO2 (69 g/mol) in the original sampleFrom a 10-mL sample, a 1-mL aliquot was taken and diluted to 100mL. From this, a 5-mL aliquot was taken and diluted to 20mL.The final 20mL was found to have a concentration of 0.004M analyte X.What is the concentration of analyte X in the 10-mL sample?20 ml of 0.1 N Ammonia diluted to 60 ml with water. (kb = 1.8 x 10-5) pH = pKw –pKb +;logC What is the p'H of the analyte?
- I was just wondering how you got the 4.0 x 10-4 for the acidionzation constant.Describe how to prepare a 2.5% 48 ml agarose gel with 1X TBE buffer.g 2.png Average absorbance, .129 +0.128 +0.127)/3 = 0.128 Chrome Concentration of Females of Fe volume Q Molarity of Fe(NO₂)) = 0.2M Volume of Fe(NO₂)); = 5.00mL Moles of Fe³+= Molarity x Molarity x volume(L) Moles of Fe³* = 0.2M x 0.0054 = 10³mole 10-mole 500 x 10-3=0.002M [Fe³+] = [SCN¯] = X = ✪ [Fe³] = 0.002mol/L nknown concentrations to determine [FeSCN]at equilibrium in solution 8: Y = 4290X - 0.068 72% (0.127 + 0.068) 4290 0.127=4290X - 0.068 25ml Fe³+ x 0.002 mol/L-¹ 100mL 100% = 4.5 x 10-5mol/L 20ml SCN X 0.002 mol/L-¹ 100mL = 5.00 x 10^4 mol/L^-1 = 4.00 x 10 mol/L-1 W Flask 8 Flask 9 Flask 10 Flask 11 3.png 4.png Part 3: Q8 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: 09 Flask 8 Flask 9 Flask 10 Flask 11 [Fe³+ (mol/L) 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 5.00 x 10-4 Average absorbance 0.127 0.166 0.222 69% 0.308 100% [FESCN¹ (mol/L) 4.5 x 10- 5.4 x 10 6.76 x 10-5 8.76 x 10- [SCN (mol/L) 4.00 x 10-4 4 x 10-4 7 x 10-4 1x 10-³ 3 7.png Place the results from calculations 9 and 10 into…
- The kinetics of hydrolysis of acetylsalicylic acid (aspirin) under certain conditions of temperature, pH, type of buffer and strength ionic, can be followed by multicomponent spectrophotometry. When performing a calculation of optical constants, the following data were obtained: Solution C. mg/100 mL A in λ (276nm) A in λ (290nm) Ac. acetylsalicylic ( AAS) 0.202 0.102 0.031 Ac. salicylic (AS) 0.198 0.158 0.101 Reaction: AAS + H2O → AS + CH3COOH In a kinetic study, after a certain time, 1 mL of the solution was taken from the reactor and diluted to 10 mL with water. distilled. Then when proceeding to the spectrophotometric measurement, the last solution presented the absorbances of 0.244 and 0.102 for the lengths of 276 and 290 nm respectively. What are the concentrations of ASA and AS in mg/L, at that instant in the reactor? Note: Acetic acid does not absorb at either wavelength.Q: 1: The distribution constant for iodine between an organic solvent and HO is 85. Find the concentration of I, remaining in the aqueous layer after extraction of 50.0mL of 1.00 X 103 M I2 with the following quantities of the organic solvent: (a) 50.0 mL; (b) two 25.0 mL portions; (c) five 10.0 mL portions.The Kjedahl procedure was used to analyze 256 µL of a solution containing 37.9 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.033 6 M HCl, and the remaining acid required 6.34 mL of 0.010 M NaOH for complete titration. What is the weight percent of nitrogen in the protein? wt%
- You prepare a buffer solution from 10.0 mL of 0.100M MOPS (3‑morpholinopropane‑1‑sulfonic acid) and 10.0 mL of 0.075 M NaOH. Next, you add 1.00 mL of 4.15×10−4 M lidocaine to this mixture. Denoting lidocaine as L, calculate the fraction of lidocaine present in the form LH+. MOPS Ka = 6.3 * 10^-8 Lidocaine Kb = 8.7 * 10^-7 ( Please type answer note write by hend )Q: 1: The distribution constant for iodine between an organic solvent and H,0 is 85. Find the concentration of I; remaining in the aqueous layer after extraction of 50.0ml. of 1.00 x 10 M I with the following quantities of the organic solvent: (a) 50.0 ml.; (b) two 25.0 ml. portions; (c) five 10.0 ml. portions. Q: 2: An acidic solute, HA, has an acid dissociation constant of 1.00 x10, and a partition coefficient between water and benzene of 3.00. Calculate the extraction efficiency when 50.00 ml. of a 0.025 M aqueous solution of HA buffered to a pH of 3.00, is extracted with 50.00 mL of benzene. Repeat for cases in which the pH of the aqueous solution is buffered to 5.00 and 7.00.In how much volume of diluted sulfuric acid should you dissolve a multivitamin tablet of approximately 1700 mg of Vitamin C to back analyze 10.00 mL of that solution, with 25.00 mL of 0.01 M KIO3 and 0.04 M thiosulfate to use approximately 8-10 mL of titrant ? You have 25, 50, 150, 250 and 500 mL flasks.