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- In the last column in the data table, it says that it's about voltage(v) divided by current(A) is equal to ohms so V/A = ohms. So if it's V/A and if you divide them to get the slope it's (y2-y1)/(x2-x1) then shouldn't V be the y value and A be the x value? And can you also try to use a line of best bit instead of drawing the line through each dot?For each of the capacitors below, calculate the following:(a) The equivalent capacitance for this circuit. (b) The potential drop across each capacitor. (c)Thecharge stored in each capacitor. Here, ?1 = 10 ??, ?2 = 10??, ?3 = 10?? . (Hint: You don’t need to docomplicated math here).a) _______________b) _______________c) _______________If the Ammeter (represented by G:Galvanometer) would read OA in the circuit given in Figure 3-1 of your lab instructions, what would be the value of R2, if R1=152.90, R3=26.60 and R4=245.90. Give your answer in units of Ohms with 1 decimal.
- Part a: what is the equivalent capacitance of the circuit shown above? Give your answer in microfarads. part b: what is the charge on the 4.0 mu*F capacity? Give your answer in microcoulombs par t c:What is the voltage on the 4mu*F capacitor ? Give your answer in Volts part c What is the voltage on the 2.0uF capacitor? Give your answer in Volts part d :Part (b): Watts, volts, and ohms are SI units that can be expressed in the 'base' SI units as follows: kg-m² 53 ohm = kg-m² $³.A21 watt = volt= bottle cm kg.m² $3.A' (Recall that 'A' is the abbreviation for an ampere.) Use algebra and the equation at the top of the page (P=V²/R) to show that the base SI units for watts equal the base SI units for volts²/ohms. You do not need any numbers in this algebraic exercise. Instead, treat each of the base SI units (kg, m, s, A) as if it were an algebra variable (like x or y). Start with the following equation and substitute the base SI units for watt, volt, and ohm: watt = volt² ohmName The voltage on the capacitor when it is connected to a resistor R follows an exponential rule: Section # capacitor is gradually released as current in the circuit. The energy stored in the capacitor is dissipated in the Pre-lab EM-7 Voltage on a capacitor in an RC Circuit capacitonarged capacitor (at potential Vo) is connected in series with a resistor, the charge stored in the resistor as heat. = Vge (1) where t is the time constant, 1= RC. Vo is the initial voltage on the capacitor when 7= 0. cironpacitance is 220 µF, and the time constant t is 22 seconds, what is the value of the resistance in the circuit? R = In the capacitor is charged to a voltage Vo = 20 V. use this initial value and time constant 22 s to calculate the votage on the capacitor in the circuit at every 5 seconds, List the results in the following table. time t (s) Voltage V (V) V/Vo In (V/Vo) 10 15 20 25 30 35 40 45 50 After the voltage values are calculated, calculate the ratio of V/Vo and In ( V/Vo). EM-7P.1…
- Solve the following problems. identify the given, the unknown, give the formula to be used, show the solution, and express the final answer into 2 decimal places. You can use a separate sheet of paper in solving the problem. 1. Find the current along a circuit if the voltage is 110 V with a resistance of 22 Ohms. and Given. Unknown: and Unknown: 3. Calculate for the voltage supplied to a load if the current is 2.5 A and the resistance is 10.80 Ohms. and Given: Unknown: Solution: Performance Task Formula: Solution: Final Answer: 2. What is the resistance of a bulb with a current of 0.72 A that is connected to a 110 V supply. Given: Formula: Solution: Final Answer: Formula: Final Answer:An electron is fired at a speed v = 3.1 x 10° m/s and at an angle 0, = 36.8° between two parallel conducting plates as shown in the figure. If s 1.8 mm and the voltage difference between the plates is AV = 98.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. !!Please fill out the template with the work for this problem. Note that you need to have a picture, a list of knowns and unknowns, the general equation/s you will use, and the math steps to solve for the unknown, Only plug in the numbers after you have solved for the unknown, and the answer with units included. Problem 1: A negative charge of q = -8.3 × 10-17C and m = 1.2 × 10-26 kg enters a magnetic field B = 1.3 T with initial velocity v = 410 m/s, as shown in the figure. The magnetic field points into the screen. Calculate the magnitude of the magnetic force F on the charge, in newtons.
- Given that R1 = 100 ohms, R2 = 250 ohms, R3 = 350 ohms, and R4 = 100 ohms, how would you find the following for the current pictured? I think I've gotten parts a and b, but I really need to be able to understand. I've never taken a physics class before. Thank you!An electron is fired at a speed v 4.3 x 10 m/s and at an angle 8 = 39.7 between two parallel conducting plates as shown in the figure. If s 1.7 mm and the voltage difference between the plates is AV= 99.8 V, determine how close, w. the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.Consider the following. (a) A rectangular block has the dimensions exw xh. When a battery with a voltage Vis connected across the end faces as shown in the left figure above, a current I, flows through the circuit. If the same battery is connected across the top and bottom faces of the block as shown in the right figure, what is the current Iz that flows through the circuit? Give your answer in terms of I1. (Use the following as necessary: {, w, h, I1) Iz = (b) Suppose { = 4.00 cm, w = 2.2 cm, and h = 1.00 cm; the battery voltage is 1.5 V and I = 3.30 A, determine the value of I2. A