Book the readings as shown in Figure Q4by Rise and Fall method. Compute all elevations, and show the arithmetic check and the resulting error in closure. If the allowable closing error is ±24√K, and the total distance covered is 200 meters, is the closing error acceptable? What kind of action should be taken? 5.11 4.66 3.98 1.20 4.42 4.72 4.30 2.01 F | H z t TP1 ·00+0 BM61 Elevation 321.70 -09+0 1+00- Figure Q4 1+50- 1.80 TP2 Elevation 327.74 1+75-

Book the readings as shown in Figure Q4by Rise and Fall method. Compute all elevations, and show the arithmetic check and the resulting error in closure. If the allowable closing error is ±24√K, and the total distance covered is 200 meters, is the closing error acceptable? What kind of action should be taken? 5.11 4.66 3.98 1.20 4.42 4.72 4.30 2.01 F | H z t TP1 ·00+0 BM61 Elevation 321.70 -09+0 1+00- Figure Q4 1+50- 1.80 TP2 Elevation 327.74 1+75-

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Given the three-wire leveling note below, find the elevation of BM2 and perform the customary arithmetic check. Sta BM1 TP1 TP2 TP3 BM2 Hair Rgds 1.152 0.935 0.718 1.713 1.440 1.167 2.784 2.350 1.916 0.913 0.730 0.547 Backsight Mean Rgds (#1) (#4) (#7) S (#2) HI (#3) Hair Rgds Foresight Mean Rgds S 1.177 0.899 0.621 1.905 1.537 1.169 1.450 1.177 0.904 2.210 1.714 (#8) (#9) 1.218 (#5) Elev 450.545 (#6) (# 10)
Part C Compute the linear misclosure. Express your answer in feet to three significant figures. IΫΠ ΑΣΦ ↓↑ vec Submit Part D Compute the relative precision. Express your answer to three significant figures. 1: Request Answer 195| ΑΣΦ. 41 vec Submit Request Answer ? ? ft
1- Complete the set of differential leveling using Rise and Fall Method, notes in Table and perform the arithmetic check. Elevation BM1 is 178.570 m. 1.150 3.112 0.911 2.470 2.814 1.00 1.219 2.890 0.710 2500 3.364 0,818 5 2.412 1,010 3 BM1 STATION BACKSIGHT FORESIGHT RISE (+) FALL (-) ELEVATION
ANSWER KEY: PROBLEM 5.10K1=102.2495mPROBLEM 5.11 D=150.7275m∆h= 33.8483m
Q2/ Complete the settlement table below and verify the correctness of the calculations. Then check the correctness of the work, bearing in mind that the length of the leveling line is 2,250 meters, bearing in mind that the required level of leveling is the third. Find the closing error and adjust the levels if necessary, suppose that the error equal for all points. Elevation Station B.M1 TP1 TP2 TP3 TP4 TP5 TP6 BM1 B.S 1.23 0.955 1.332 1.652 2.558 2.465 2.882 H.I F.S 1.735 2,642 3.000 2.524 2.221 0.755 0.218 50,000
DIFFERENTIAL LEVELING. Complete the differential level notes shown below and perform the customary arithmetic. STA BS HI FS ELEVATION ВМ10 2.085 137.450 m ТР1 2.015 0.982 ТР2 1.864 1.428 ТРЗ 0.579 1.527 BM11 0.423 2.423 TP4 1.446 1.807 ТР5 1.778 1.725 ТР6 2.051 2.339 TP7 2.920 1.005 ВМ12 3.186 2.358 ТР8 2.805 0.995 ТР9 0.774 1.206 ВМ13 0.603
The observed lengths of the sides (in feet) of a five-sided closed polygon traverse are as follows: AB= 202.74, BC = 285.87, CD= 499.37, DE = 321.33, and EA = 382.78. (Note: Assume units of feet for all distances.) The preliminary azimuths obtained after balancing the angles are as follows: AB= 138° 16'27", BC = 67°02′46", CD= 354°22'24", DE = 256° 13'01", EA = 185°29/20". Compute the departures of the sides. Express your answers in feet to five significant figures and separated by commas. AB, BC, CD, DE, EA = Part B ||| ΑΣΦ ΑΣΦ AB, BC, CD, DE, EA = vec Compute the latitudes of the sides. Express your answers in feet to five significant figures and separated by commas. [ΠΙ —| ΑΣΦ | w vec ? ? ft, ft, ft, ft, ft ft, ft, ft, ft, ft
Book the readings as shown in Figure Q5 by Rise and Fall method. Compute all elevations, and show the arithmetic check and the resulting error in closure. If the allowable closing error is ±24√K, and the total distance covered is 200 meters, is the closing error acceptable? What kind of action should be taken? 5.11 4.66 3.98 1.20 1.80 Rod TP2 Elevation 327.74 Figure Q5 4.72 4.42 BM61 Elevation. 321.70 4.30 2.01 TP1 0+00-7 0+50- 1+00- 1+50- 1+75- |
Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a chain line at common interval of 10 meter which are listed below in table. First reading is taken on bench mark of 105.615 meter reduce level. Station Points Chainage (m) Staff Readings (m) Remarks BS IS FS 1 00 3.005 BM 2 10 2.285 3 20 1.560 4 30 1.785 5 40 2.105 6 50 2.875 3.105 CP 1 X 53.35 3.465 7 60 3.955 8 70 3.120 9 80 3.015 10 90 2.580 11 100 1.955 CP 2 Determine the reduce levels of all points using both line of collimation and rise and fall method. (Present your answer in table form).
A. TACHEOMETRY 1. A transit is set up at a distance back of the zero end of a level base line 240 m. long. The base line being marked by stakes at every 30 m. A rod is then held at successive stations along the base line. The stadia intervals at each location of the rod are tabulated below. It is required to determine the stadia interval factor of the instrument. Distance Stadia Distance Stadia Intercept Intercept 30 0.297 150 1.482 60 0.591 180 1.776 90 0.885 210 2.073 120 1.188 240 2.367
1. Complete the differential leveling notes shown in Table 1 and perform the arithmetic check. Show sample calculations of your work. Then draw a neat profile view sketch showing the ground elevations of all of the stations and the various locations of the level and level rod. Station BM 3 TP 1 TP 2 TP 3 BM 3 BS (m) 1.613 1.425 1.307 1.340 Table 1 HI (m) FS (m) 1.927 1.710 1.273 0.780 Elevation (m) 133.005
1) Complete the missing data and determine the difference in elevation of BM1 and BM2. Show complete solution. STA BS HI FS ELEV (m) BM1 1.097 504.233 TP1 1.661 1.998 ТР2 1.012 2.015 ТРЗ 1.905 2.396 BM2 2.761