Bob selects independent random samples from wo populations and obtains the values p = .700 and p2 onfidence interval for p1 – P2 and gets: 0.500. He constructs the 95% %3D 0.200 + 1.96(0.048) = 0.200 ±0.094. Note that 0.048 is called the estimated standard rror of p1 – P2 (the ESE of the estimate). om wants to estimate the mean of the success ates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (pi + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (Pi + P2)/2. Hint: The answer has our usual form: Pt. est. +1.96 × ESE of the estimate.
Bob selects independent random samples from wo populations and obtains the values p = .700 and p2 onfidence interval for p1 – P2 and gets: 0.500. He constructs the 95% %3D 0.200 + 1.96(0.048) = 0.200 ±0.094. Note that 0.048 is called the estimated standard rror of p1 – P2 (the ESE of the estimate). om wants to estimate the mean of the success ates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (pi + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (Pi + P2)/2. Hint: The answer has our usual form: Pt. est. +1.96 × ESE of the estimate.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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