Based on the restriction enzyme specificities given below, what was the enzyme utilized to produce the overhangs in the cut DNA sample? Restriction Enzyme Specificities: ... GAATTC. CTTAAG. PstI .CTGCA.. GACGTC. ECORI Hpal GTTAAC.. CAATTG.
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- Based on the restriction enzyme specificities given below, which will generate blunt ends? Restriction Enzyme Specificities: ... ECORI .GAATTC... .CTTAAG... .GTTAAC... CAATTG. CTGCAG.. GẠCGTC... Hpal PstI Hind III ... AAGCTT... ITCGAA... Bam HI ...GGATCC... ..CCTAGG... A) EcoRI B) BamHI c) Hindll D Hpal E PstlA small DNA molecule was cleaved with several different restriction nucleases, and the size of each fragment was determined by gel electrophoresis.The following data were obtained. (a) Is the original molecule linear or circular?(b) Draw a map of restriction sites (showing distances between sites) that isconsistent with the data given.(c) How many additional maps are compatible with the data?(d) What would have to be done to locate the cleavage sites unambiguouslywith respect to each other?Based on the restriction enzyme specificities given below, which will generate blunt ends? Restriction Enzyme Specificities: GAATTC... Hpal ..СТТААG... ECORI ...GTTAAC... ...CAATTG... PstI ..CTGCAG... .. GĄCGTC... OTAS Hind II... AAGCTT... Bam HI ...GGATCC... ..CCTAGG... ...TTCGAA... ↑ ↑ HindlII B Pstl BamHI EcoRI Hpal
- he gel presented here shows the pattern of bands of fragments produced with several restriction enzymes. (a) From your analysis of the pattern of bands on the gel, draw the correct restriction map and explain your reasoning. (b) The highlighted bands (magenta) in the gel hybridized with a probe for the gene pep during a Southern blot. Where in the gel is the pep gene located?Consider a partial restriction digestion, in which genomic DNA is exposed to a small, limiting amount ofa restriction enzyme for a very short period of time.a. Would the resultant fragments be longer or shorteror the same size as those produced by a completedigestion?Restriction sites are palindromic; that is, they read the same in the5' to 3' direction on each strand of DNA. What is the advantage ofhaving restriction sites organized this way?
- Single and double digestion of plasmid pMCS326 were performed using the restriction enzymes AluIII and EcoRV. DNA fragments were shown in an electrophoretogram below. Construct a restriction map of plasmid pMCS326 for enzymes AluIII and EcoRV. (Create restriction mapping with explanation)Mouse genomic DNA is treated with a restriction endonuclease and electrophoresed in an agarose gel. A radioactive probe made from the human gene rxr-1 is used to perform a Southern blot. The experiment was repeated three times. Explain the results of these repeated experiments:DNA samples from four individuals were cleaved with the same MW restriction endonuclease. The DNA fragments were separated by gel clectrophoresis, transferred to a membrane, and hybridized with a 12 kb 10 kb DNA probe complementary to a region between sites C and D (see 8 kb hybridization line). The image of the southern blot shows the labeled DNA bands and 6 kb molecular weight (MW) markers. The lane labels I, II, III, and IV -5 kb correspond to individuals I, II, III, and IV. Assume that fragments such as C-D and C-E are clearly resolved in this gel system. Fragment sizes are as given: A-B is 4 kb, B-C is I kb, C-D is 5 kb, and D-E is 650 bp. Individual I has five cleavage sites (A, B, C, D, and E) for the restriction endonuclease. DNA homologous to probe Which individual has at least one point mutation that eliminates restriction site C only? O II IV cannot be determined II Which individual has at least one point mutation that climinates restriction sites B and C? III O IV cannot be…
- What restriction enzyme (or enzymes) would you use to cut the following... (Gene of Interest is Bolded) 1 tctagagtca tgaaacaaca aaaacggctt tacgcccgat tgctgacgct gttatttgcg 61 ctcatcttct tgctgcctca ttctgcagca gcggcggcaa atcttaatgg gacgctgatg 121 cagtattttg aatggtacat gcccaatgac ggccaacatt ggaagcgttt gcaaaacgac 181 tcggcatatt tggctgaaca cggtattact gccgtctgga ttcccccggc atataaggga 241 acgagccaag cggatgtggg ctacggtgct tacgaccttt atgatttagg ggagtttcat 301 caaaaaggga cggttcggac aaagtacggc acaaaaggag agctgcaatc tgcgatcaaa 361 agtcttcatt cccgcgacat taacgtttac ggggatgtgg tcatcaacca caaaggcggc 421 gctgatgcga ccgaagatgt aaccgcggtt gaagtcgatc ccgctgaccg caaccgcgta 481 atttcaggag aacacctaat taaagcctgg acacattttc attttccggg gcgcggcagc 541 acatacagcg attttaaatg gcattggtac cattttgacg gaaccgattg ggacgagtcc 601 cgaaagctga accgcatcta taagtttcaa ggaaaggctt gggattggga agtttccaat 661 gaaaacggca actatgatta tttgatgtat gccgacatcg attatgacca tcctgatgtc 721 gcagcagaaa ttaagagatg gggcacttgg tatgccaatg…Consider a partial restriction digestion, in which genomic DNA is exposed to a small, limiting amount ofa restriction enzyme for a very short period of time.a. Would the resultant fragments be longer or shorteror the same size as those produced by a completedigestion?b. If you prepared genomic DNA from a tissue sample containing millions of cells, would the fragments produced by partial digestion of DNA fromall of these cells be the same or different?A group of overlapping clones, designated A through F, is isolated from one region of a chromosome. Each of the clones is separately cleaved by a restriction enzyme, and the pieces are resolved by agarose gel lectrophoresis,with the results shown below. There are nine different restriction fragments in this chromosomal region, with a subset appearing in each clone. Using this information, deduce the order of the restriction fragments in the chromosome.