Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Fe(CN), ³(aq) + N₂H₂+ (aq) ⇒ Fe(CN) + (aq) + N₂(g) (b) Clo (aq) + I₂(s) ⇒ Cl(aq) + 103 (aq) 5 0 Fe(CN)6³ +7 XN₂H₂ +0 H₂O 2 clo + 1 H₂O (c) Cro4² (aq) + C₂042(aq) = Cr(OH)3(s) + CO₂(g) OH + CrO₂² +1 OH + 10 X Tl₂O3 + I₂ + 0 H₂O (d) Tl₂O3(s) + NH₂OH(aq) = TIOH(s) + N₂(g) X H₂O XC₂0₂² +0 X NH₂OH + H+ + O H+ + 1 OH + 8 X OH + H₂O=4 H₂O=5 H₂O = 2 XH₂0= Fe(CN)64 +7 Cl² + 2 Cr(OH)3 + 2 X TIOH(s) + XN₂ + 35 10₂ + 2 XH+ XN₂ + H+ + X CO₂ + 10 x

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 46PS: Balance each of the following equations, and then write the net ionic equation. Show states for all...
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Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.)
(a) Fe(CN)6³(aq) + N₂H5+ (aq) Fe(CN) 6+ (aq) + N₂(g)
4
+0
5
0
(b) Clo (aq) + I₂(s) ⇒ Cl(aq) + 10₂ (aq)
Fe(CN)6³ +7
H₂O
2
CIO +1
H₂O
OH +
(c) Cro4² (aq) + C₂042 (aq) = Cr(OH)3(s) + CO₂(g)
CrO4² +1
OH +0
XN₂H5 +0
X Tl₂O3 +
H₂O
X H₂O
1₂ +0
(d) Tl₂O3(s) + NH₂OH(aq) = TIOH(s) + N₂(g)
XC₂04² +0
X NH₂OH +
H+ + 0
H+ +1
OH +8
X OH +
H₂O 4
H₂O=5
H₂O = 2
| H2O=
Fe(CN) 64 + 7
CI + 2
Cr(OH)3 + 2
X TIOH(s) +
XN₂ + 35
103 +2
* H*
XN₂ +
H+ +
X CO₂ + 10
X
Transcribed Image Text:Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Fe(CN)6³(aq) + N₂H5+ (aq) Fe(CN) 6+ (aq) + N₂(g) 4 +0 5 0 (b) Clo (aq) + I₂(s) ⇒ Cl(aq) + 10₂ (aq) Fe(CN)6³ +7 H₂O 2 CIO +1 H₂O OH + (c) Cro4² (aq) + C₂042 (aq) = Cr(OH)3(s) + CO₂(g) CrO4² +1 OH +0 XN₂H5 +0 X Tl₂O3 + H₂O X H₂O 1₂ +0 (d) Tl₂O3(s) + NH₂OH(aq) = TIOH(s) + N₂(g) XC₂04² +0 X NH₂OH + H+ + 0 H+ +1 OH +8 X OH + H₂O 4 H₂O=5 H₂O = 2 | H2O= Fe(CN) 64 + 7 CI + 2 Cr(OH)3 + 2 X TIOH(s) + XN₂ + 35 103 +2 * H* XN₂ + H+ + X CO₂ + 10 X
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