Only typed explanation otherwise leave it At 25°C, what are the molar H3O+ and OH concentrations ina. 0.0430 M C6H5 COOH (Ka (C6H5 COOH) = 6.28 × 10−5 )?[H₂O+] =[OH¯] =Mb. 0.0410 M HN3 (K₁ (HN3) = 2.2 × 10−5)?[H₂O+]-[[OHT] =Mc. 0.380 M hydroxylamine hydrochloride (K₂ (HONH3 +) = 1.10 × 10¯º)?[H₂O+] =[OH-] ==MMMM

Given,(a) Molarity of C6H5COOH = 0.0430 M Ka of C6H5COOH = 6.28 x 10-5(b) Molarity of HN3 =…

At 25°C, what are the molar H3O+ and OH concentrations in a. 0.0430 M C6H5 COOH (K₂ (C6H5 COOH) = = = 6.28 × 10-5)? [H3O+]-[ M [OH¯] = M b. 0.0410 M HN3 (K₁ (HN3) = 2.2 × 10-5)? [H₂O+]= [OH-] = M c. 0.380 M hydroxylamine hydrochloride (K₂ (HONH3+) = 1.10 × 10¯º)? [H₂O+] = [OH¯] = M M M

At 25°C, what are the molar H3O+ and OH concentrations in a. 0.0430 M C6H5 COOH (K₂ (C6H5 COOH) = = = 6.28 × 10-5)? [H3O+]-[ M [OH¯] = M b. 0.0410 M HN3 (K₁ (HN3) = 2.2 × 10-5)? [H₂O+]= [OH-] = M c. 0.380 M hydroxylamine hydrochloride (K₂ (HONH3+) = 1.10 × 10¯º)? [H₂O+] = [OH¯] = M M M

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.66PAE

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