At -13.8 °C the concentration equilibrium constant K = 5.8 × 10 for a certain reaction. Here are some facts about the reaction: If the reaction is run at constant pressure, 107. kJ/mol of heat are released. ⚫ The constant pressure molar heat capacity C р = 2.18 J-mol¹. K¹ The initial rate of the reaction is 8.3 mol·L¹·s¹. Yes. Using these facts, can you calculate K at -21. °C? No. If you said yes, then enter your answer at right. Round it to 2 significant digits. 0 x10

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At 13.8 °C the concentration equilibrium constant K
-5
5.8 x 10
for a certain reaction.
Here are some facts about the reaction:
• If the reaction is run at constant pressure, 107. kJ/mol of heat are released.
• The constant pressure molar heat capacity C
P
= 2.18 J-mol
1
K-1
■The initial rate of the reaction is 8.3 mol·L
-1
'S
Using these facts, can you calculate K at -21. °C?
○ No.
If you said yes, then enter your answer at right. Round it to
2 significant digits.
Yes.
x10
If you said no, can you at least decide whether K at
-21. °C will be bigger or smaller than K at -13.8 °C?
Yes, and K will be
bigger.
Yes, and K will be
smaller.
No.
G
Transcribed Image Text:At 13.8 °C the concentration equilibrium constant K -5 5.8 x 10 for a certain reaction. Here are some facts about the reaction: • If the reaction is run at constant pressure, 107. kJ/mol of heat are released. • The constant pressure molar heat capacity C P = 2.18 J-mol 1 K-1 ■The initial rate of the reaction is 8.3 mol·L -1 'S Using these facts, can you calculate K at -21. °C? ○ No. If you said yes, then enter your answer at right. Round it to 2 significant digits. Yes. x10 If you said no, can you at least decide whether K at -21. °C will be bigger or smaller than K at -13.8 °C? Yes, and K will be bigger. Yes, and K will be smaller. No. G
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