Assume that one of Merida's sons, who is heterozygous for orange hair color, married a girl that was also heterozygous. Create a Punnett square to show the possibilities that would result if they had children. a. List the possible genotypes and phenotypes for their children. b. What are the chances of a child with orange hair? c. What are the chantes of a child with yellow?
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- Amna and Ali are suffering with hypochondroplasia. They want to know if they have any chances of having children with normal height and also, if they could have stillborn children. Use a punnett square to help you explain their chances for all phenotypes.In humans, having dimpled cheeks is dominant to non-dimpled cheeks. Is it possible that two dimpled adults have a non-dimpled child? Use a Punnett square to explain your answer. If it is possible, what is the probability of this occurring?If Marge’s father is a heterozygous tall Zork and her mother is a short Zork, what isMarge’s genotype?Complete the Punnett square to show the possible genotypes that would result to help you determine Marge’s genotype.What is Marge’s genotype?
- Using the pedigree chart shown answer question . What is the likelihood that the progeny of IV-3 and IV-4 will have a widow’s peak?A line perpendicular to a marriage line indicates the offspring. If the line ends with either a circle or a square, the couple had only one child. However, if the line is connected to another horizontal line, then several children were produced, each indicated by a short vertical line connected to the horizontal line. The first child born appears to the left and the last bor to the right. a. How many children did the first couple (couple in row D) have? b. How many children did the third couple (couple in row III) have?In humans, having freckled skin (F) is dominant. Assume that a homozygous recessive man and a heterozygous woman have a child. a. What is the woman's phenotype? b. Show the Punnett square for the cross. С. What is the child's probability of having no freckles? Uunt
- Red hair is recessive to dark hair. If red-headed Jack fathers a child with red-headed Lisa, what are the chances that their children will have red hair? Show you work using a Punnett square.A. heterozygous blue-eyed man is marrying a homozygous brown-ayed woman. Determine the ratio of the following from the offspring. B. Genotype C. PhenotypeWhy is there no trait (letter) on the y chromosome for males in this pedigree? A. Because the trait is X-linked (on the X chromosome) B. Because Ms. Premo made a mistake C. Because we never write anything on the y chromosome
- Aurora met Prince Phillip at the dance. Both of them are heterozygous for their large eyes, which is dominant over small eyes. Create a Punnett square to show the possibilities that would result if they had children. (use E for dominant and e for recessive) a. List the possible gehotypes and phenotypes for their children. b. What are the chances of a child with small eyes? out of or C. What are the chances of a child with large eyes? out of or 00A normal-hair man married a normal-hair woman who is heterozygous for the character. 1. Give the genotypes of the man and the woman for both characters.2. Give the possible genotypes and phenotypes and their ratios in the offspring.The pedigree below tracks the inheritance of a genetic disorder through a family's generation. I II 1 2 3 4 III 2 (i) Predict the mode of inheritance of the genetic disorder. Explain your answer. If III-2 marries a woman who has normal parents and a brother affected by the genetic disorder, what is the probability that they will give birth to an affected child? (ii) Extend the pedigree tree to include the family of III-3 spouse and the fourth generation. Explain your answer. (iii) Obligate carriers are individuals who must carry the mutation that produces the trait. Please list the obligate carriers in the pedigree shown above.