ase to phpMyAdmin, you should be able to view it’s four tables. 1) From the countrylanguage table, extract/generate two columns: Language and COUNT(*), rank the frequency of languages in decreasing order, the COUNT(*) column should indicate the number of appearance for each different language. Provide the code and the first screenshot for the first 25 rows of the

ase to phpMyAdmin, you should be able to view it’s four tables. 1) From the countrylanguage table, extract/generate two columns: Language and COUNT(), rank the frequency of languages in decreasing order, the COUNT() column should indicate the number of appearance for each different language. Provide the code and the first screenshot for the first 25 rows of the

Np Ms Office 365/Excel 2016 I Ntermed

1st Edition

ISBN:9781337508841

Author:Carey

Publisher:Carey

Chapter5: Working With Excel Tables, Pivottables, And Pivotcharts

Section: Chapter Questions

Problem 10RA

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Note: Use MYSQL Create a database named book-collection-db and table named: bookcollect. Your tableshould contain the following columns: Title, Author, Genre (Children’s, Romance,Thriller, Fantasy, etc.), Publisher, Copyright Date, ISBN Number, Category (Fiction/Nonfiction), Overview, Link Where to Buy, and Price. Create 30 rows containing list of bookwith varied genre.
Refer to the film and inventory tables of the Sakila database. The tables in this lab have the same columns and data types but fewer rows. Write a query that lists the titles of films with the fewest rows in the inventory table. This query requires a subquery that computes the minimum of counts by film_id: SELECT MIN(count_film_id) FROM ( SELECT COUNT(film_id) AS count_film_id FROM inventory GROUP BY film_id ) AS temp_table; This subquery is provided in the template.
Views in SQL are kind of virtual tables. A view also has rows and columns as they are in a real table in the database. We can create a view by selecting fields from one or more tables present in the database. A View can either have all the rows of a table or specific rows based on certain conditions. Under what circumstances would you create a View?
The Employee database contains a page displaying summary information, including EMPNO, ENAME, JOB, HIREDATE, SAL and DEPTNO columns from the EMP table. Create a PL/SQL block with scalar variables to retrieve this data and then display it on screen. An initialized variable should provide the EMPNO value. Test the block using the employee number 7369.
Create a PL/SQL function to increment the salary of all employees of an organization by 15%, and for employees with department ID 101 give another 10% hike on the updated salary. The function will be called as -> Select new_salary(10000, 101) from dual; The first parameter is the current salary and the second parameter is the department ID. Also, write the query to update the salary of all records of the salary column in the employee table.
You are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. The state names are abbreviated. You want to check for state names that are greater than 2 characters long. You write the SQL query below. Add a LENGTH function that will return any state names that are greater than 2 characters long.
Create a PL/SQL function to increment the salary of all employees of an organization by 20%, and for a department with ID 102 give another 5% hike on the updated salary. The function will be called as -> Select new_salary(15000, 120) from dual; The first parameter is the current salary and the second parameter is the department ID. Also, write the query to update the salary of all records of the salary column in the employee table.
Write a PL/SQL block to read through rows in the countries table for all countries in region 5 (South America region). Country name must be entered by the user. For each selected country, display the country_name, national_holiday_date, and national_holiday_name. Use a record structure (user defined) to hold all the columns selected from the countries table. NOTE: BOLD SENTENCES ARE IMPORTANT/ IS A MUST in the code.
Write a T-SQL query to display the emp code, emp lname, employee job code, from the employee table joining the job table where the employee job code equals the job table job code. Order the output by employee job code. Copy and paste the query and the output into your assignment document. (hint: use table aliases) /* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE…
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SQL Table: CREATE TABLE employees ( employee_id INT PRIMARY KEY, first_name VARCHAR(255), last_name VARCHAR(255), email VARCHAR(255) UNIQUE, phone_number VARCHAR(255), hire_date DATE, job_id VARCHAR(255), salary DECIMAL(10,2), commission_pct DECIMAL(5,2), manager_id INT, department_id INT, FOREIGN KEY (manager_id) REFERENCES employees(employee_id), FOREIGN KEY (department_id) REFERENCES departments(department_id)); CREATE TABLE departments ( department_id INT PRIMARY KEY, department_name VARCHAR(255), manager_id INT, FOREIGN KEY (manager_id) REFERENCES employees(employee_id)); INSERT INTO employees (employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)VALUES (1, 'John', 'Doe', 'john.doe@example.com', '555-555-5555', '2022-01-01', 'IT_PROG', 8000, 0.2, 3, 10), (2, 'Jane', 'Smith', 'jane.smith@example.com', '555-555-5556', '2022-02-01', 'IT_PROG', 9000,…
SQL ( ORACLE SQL DEVELOPER ) : THIS IS FIRST , SECOND AND THIRD TABLE for the Task 1 to solve : create table author_45( auth_name char(50), gender char(1), age number(3), nationality char(50), PRIMARY KEY (auth_name) ); create table book_45( isbn number(10), title char(50), ver_no number(2), publisher char(50), PRIMARY KEY (isbn) ); create table writtenBy_45( isbn number(10), auth_name char(50), yr_published number(4), price number(3), no_copy number(4), PRIMARY KEY (isbn,auth_name), foreign key (isbn) references book_45, foreign key (auth_name) references author_45 ); insert into author_45 values ('Benoit','F',42,'French'); insert into author_ 45 values ('Antonini','M',33,'Italian'); insert into author_ 45 values ('McAven','F',31,'Australian'); insert into author_ 45 values ('Williams','M',90,'British'); insert into book_45 values (101,'atabases',1,'Possum'); insert into book_45 values (202,'SQL Primer',2,'Hall'); insert into book_45 values…