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- : Egbabl Qe A Solution is Prefared Tby dissdlving 6g AgNoz ina 250-ml Volumetric Hask and diliting the molaurity of the Silver nityate Solution How to Volume. alculute Many millimoles Ag No3. Were dissalved7 twt Ag Noz 169-9Hat17- The percentage of protein in meat products is determined by multiplying the %N as determined by the kjeldahl method by the arbitrary factor 6.25. A sample of processed meat scrap weighing 2.000 g is digested with concd H2SO4 and Hg (catalyst) until the N present has been converted to NH&HSO.. This is treated with excess NaOH, and the liberated NH3 is caught in 50.0 mL pipetful H2SO, (1.000 ml 0.01860g NazO). The excess acid requires 28.80 mL NaOH (1.000 mL = 0.1266 g KHP). Calculate % protein in the meat scrap.Assume that 1.00 mL (1.02 g) of crude product mixture is obtained from the reactionbefore the washing steps, and the distribution constant of the product mixture in brine isK = (Cmixture/Cbrine) = 50.0. Assuming that after mixing the product mixture volume isstill 1.00 mL (i.e., the volume lost is small), and the volume of the first brine wash layeris 2.00 mL. What mass (grams) of product mixture is lost (dissolves) in the first brinewash? (See Technique 13.2, p 53.) Show work.
- Data Mass of unknown metal Cark te ?l.005g Volume of uniknown solotion CmL) Volume of HCI added Inital burct readinglmL) Final buret reading (mL) 20.00ML (mL) 15.00mL 20.SSmL 30.90ML Volume Na OH delivered (m L) Concentration of HCI: O.1708M Concentrahon of NaOH: O.1000M * Pipetted 10.35mL 20.00mL Of solution prepared in 250.0 mL volumetric flask Questions', 1. Calalate the number of moles of Na OH used for back titration? 2. Calculate the number of moles moles of metal carbonate present in 20.00mL portion of the metal Carborate soltion? 3. Calculate molar masS of 3.Calculate in knon metal carbongteElectroly Concentr X Chapter Partial P henrys la x My Q 'index.html Sodium hydroxide is a white, crystalline basic salt that readily dissociates in water to produce a strong base NaOH(s) – - Na* (aq) + OH (aq) According to the CRC Handbook of Chemistry and Physics, sodium hydroxide (NaOH; m.m. = 39.997 g mol-1; d = 2.13 g cm 3) has an aqueous solubility of 100.0g/100g at 20 °C. Below is a table of aqueous sodium hydroxide densities (in kg L-1) at varying concentrations (wt%) and temperatures (from handymath). Conc. (wt%) 0 °C 10 °C 20 °C 40 °C 60 °C 80 °C 100 °C 1.0124 1.0107 • 1.0095 1.0033 0.9941 0.9824 0.9693 2 1.0244 1.0220 1.0207 1.0139 1.0045 0.9929 0.9797 4. 1.0482 1.0444 1.0428 1.0352 1.0254 1.0139 1.0009 8 1.0943 1.0889 1.0869 1.0780 1.0676 1.0560 1.0432 12 1.1399 1.1333 1.1309 1.1210 1.1101 1.0983 1.0855 16 1.1849 1.1776 1.1751 1.1645 1.1531 1.1408 1.1277 20 1.2296 1.2218 1.2191 1.2079 1.1960 1.1833 1.1700 24 1.2741 1.2658 1.2629 1.2512 1.2388 1.2259 1.2124 28 1.3182 1.3094…C Solubility of potassium nitrate in water Sample calculation of the solubility (show work for trial 1): Trial Solubility of KNO3 | [g KNO3/100g H20.] = || ||| IV
- Q2- A 30.0 mL H2C2O4 acidified solution, was treated with 25.0 mL of 0.102 M KMnOg solution. The reaction: 2MNO4- + 5 H2C204+ 6H → 2MN2+ +10CO2 + 8H20 The excess permanganate required 8.34 mL of 0.053 M Fe2* solution, the reaction Mno“ + 5Fe?* + 8H+ g Mn* +5Fe+ + 4H20 Find the molarity of the H2C2O4 solutionon in a 1. 200 Sample was precipi toled as the hdroxide and ignited to Ferm Fez0 (0. 352 1 FW= 159-7 lmal). Fnd %Fe (AW : 55-8 glmal)in the Sample. 4 A 2-560 g of impure CCl, Sample was disselved in water and precipitated wii th excess Na Cou Selution. 1F i.245g CaGOu (FW= 12891ml) was obtained, what is the percentage f Cack (FW= mglmal) in the impure Sample? Cu: A 0-21219 sample of an organic Compound was and the Ce, was burned in a stream of oxygen, and the CO2 was Callected in a solution of BalOH), Caleulate the %C in the Sample if o.co06 g of Ba COg was hamedd (FW Ba CO, = 197.34g mol), (AW C=12 glm)1.5g sample contains sulfur S (aw=32) has been dissolved. The sulfur is precipitated as BaSO4 (mw = 233). If the weight of the precipitate is 0.65g the percentage of sulfur in the sample is
- A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 ml, aliquot was titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Another 20 mL aliquot was titrated to the BCG endpoint, using up 18.87 mL of titrant in the process. Identify the alkali components and their percent weight.You wish to undertake a 100 step countercurrent extraction of solutes A & B with distribution coefficients D= 1.5 & Da - 0.6. Suppose the volumes of mobile and stationary are equal. If fractions 28-40 and 50-68 are each pooled find the % recovery and purity of each solute. AA 79.8% recovery of 99.7% pure A B: 82.0% recovery of 86.6% pure B B. A: 72.7 % recovery of 97.0% pure A B: 89.0 % recovery of 98.9 % pure B OC.A: 82.6% recovery of 92.3% pure A B: 82.9% recovery of 91.0% pure B O D.A 92.6% recovery of 99.5% pure A 8: 67.0% recovery of 100 % pure BFor the chemical reaction HCN(aq) + KOH(aq) — H,O(l) + KCN(aq) write the net ionic equation, including the phases. net ionic equation: $ 4 R F V % 5 24 F5 T G 6 B MacBook Air Y H & 7 N F7 U * 00 8 DII FB 1 M ( 9 K DD F9 O H ) O F10 P A. option + 4) dele