Algorithm Analysis: estimate the time complexity of the following methods using Big O notation. (highlight final answer)| (a) public static void mA(int n) { for (int i = 0; i < n; i++) { System.out.print (i) (b) public static void mB (int n) { for (int i = 0; i < n; i++) { for (int j = 0; j
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- %3B for ( int i = 0; i < n; ++i ) { for ( int j= 0; j< n; ++j) { sum += f( j, 10 ); } } iii. int sum = 0; %3D Assume f(n, m) runs in O( n + m) time.JAVA Question 2: For two integers m and n, their GCD (Greatest Common Divisor) can be computed by a recursive method. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Method body: If m is 0, the method returns n. If n is 0, the method returns m. If neither is 0, the method can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n (or m % n). The recursive method cannot have loops. Note: although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. main method: Prompt and read in two numbers to find the greatest common divisor. Call the gcd method with the two numbers as its argument. Print the result to the monitor. Example program run: Enter m: 12 Enter n: 28 GCD(12,28) = 4 And here is what I have so far, package CSCI1302;import java.util.*;public class RecursionDemo { public static void…Java Program: Recursive Method There are n people in a room where n is an integer greater then or equal to 2. Each person shakes hands once with every other person. What is the total number of handshakes in the room? Write a recursive method to solve this problem with the following header:public static int handshake(int n)where handshake(n) returns the total number of handshakes for n people in the room. To get you started if there are only one or two people in the room, then:handshake(1)=0handshake(2)=1
- using System; class HelloWorld { static void Main() { int rows=21; int columns=76; for(int i=0;i<rows;i++) //for loop for printing the pattern for 21 rows { for(int j=1;j<=columns;j++) //for loop for printing the pattern in 76 columns { if((i+j)%7!=1 ) //if the addition of i and j does not give remainder of 1 when divided by 7 then Console.Write("-"); //print dash - on console else //otherwise peint a space on console Console.Write(" "); } Console.WriteLine(); //print a newline for printing on new row... } } }PROBLEM STATEMENT: Add two numbers together and return the resulting sum. public class AddTwoTogether{public static int solution(int x, int y){// ↓↓↓↓ your code goes here ↓↓↓↓return 0; Can you help me write this in JAVA. Find the output of the following code. Public class Solution{ Public static void main(String args[]){ Int i; for(i 1; i 3) continue; } System.out.println(i); }
- Compute the combinations of n things taken k at a time using both iterative and recursive methods. Both methods should use only int types for mathematical operations. If the iterative method continues to mock, that is fine, the recursive method should not. Can you please modify the following code for the given question?(Java Programming) public class Combination { private static boolean useFact; /*** Computes some combinations.* * @param args unused*/public static void main(String[] args) {for (int i = 0; i < 2; i++) {useFact = (i % 2 == 0);System.out.println(useFact ? "FACTORIAL METHOD" : "RECURSIVE METHOD");System.out.println();combination(2, 2);combination(3, 2);combination(4, 3);combination(10, 2);combination(52, 5);combination(60, 4);combination(75, 3);combination(100, 4);System.out.println();}} /*** A method which switches between the two combination methods* @param n the number of things* @param k how many to choose*/public static void combination(int n, int k)…import java.util.Scanner; public class LabProgram { // Recursive method to draw the triangle public static void drawTriangle(int baseLength, int currentLength) { if (currentLength <= 0) { return; // Base case: stop when currentLength is 0 or negative } // Calculate the number of spaces needed for formatting int spaces = (baseLength - currentLength) / 2; if (currentLength == baseLength) { // If it's the first line, don't output spaces before the first '*' System.out.println("*".repeat(currentLength) + " "); } else { // Output spaces and asterisks System.out.println(" ".repeat(spaces) + "*".repeat(currentLength) + " "); } // Recursively call drawTriangle with the reduced currentLength drawTriangle(baseLength, currentLength - 2); } public static void drawTriangle(int baseLength) { drawTriangle(baseLength, baseLength); } public static…Do not use static variables to implement recursive methods. USING JAVA 1. Using Big Oh notation, indicate the time requirement for each of the following tasks in the worst case. Describe which operations are assumed to take constant time to. After arriving at a party, you shake hands with each person there. n is the number of persons in the party. Each person in a room shakes hands with everyone else in the room. n is the number of persons in the room. You climb a flight of stairs. n is the number of stairs After entering an elevator, you press a button to choose a floor. n is the number of floors You ride the elevator from the ground floor up to the nth floor. You read a book twice. n is the number of pages in the book Using Big Oh notation, indicate the time requirement of each of the following tasks in the worst case. Display all the integers in an array of integers. Display all the integers in a chain of linked nodes. Display the nth integer in an array of integers. Compute…
- import java.util.Scanner; public class LabProgram { // Recursive method to draw the triangle public static void drawTriangle(int baseLength, int currentLength) { if (currentLength <= 0) { return; // Base case: stop when currentLength is 0 or negative } // Calculate the number of spaces needed for formatting int spaces = (baseLength - currentLength) / 2; if (currentLength == baseLength) { // If it's the first line, don't output spaces before the first '*' System.out.println(" ".repeat(spaces) + "*".repeat(currentLength)); } else { // Output spaces and asterisks System.out.println(" ".repeat(spaces) + "*".repeat(currentLength)); } // Recursively call drawTriangle with the reduced currentLength drawTriangle(baseLength, currentLength - 2); } public static void drawTriangle(int baseLength) { drawTriangle(baseLength, baseLength); } public…10. public static void methodl (int i, int num) { for (int j = 1; j <= i; j++) { " "); System.out.print (num + num *= 2; } System.out.println(); } public static void main(String[] args) { int i = 1; while (i <= 6) { methodl (i, 2); i++; }9. Ackermann's Function Ackermann's function is a recursive mathematical algorithm that can be used to test how well a computer performs recursion. Write a method ackermann (m, n), which solves Ackermann's function. Use the following logic in your method: If m = 0 then return n + 1 If n = 0 then return ackermann (m Otherwise, return ackermann(m 1, 1) 1, ackermann (m, n - 1))