Algo Question2_6 Begin i,j,nb : integer nb <- 0 Pour i = 0 to 2 Pour j = 1 to 3 nb <- nb + i End For End For Cell(1,1) <- nb End What is the value of cell (1,1)
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Algo Question2_6
Begin
i,j,nb : integer
nb <- 0
Pour i = 0 to 2
Pour j = 1 to 3
nb <- nb + i
End For
End For
Cell(1,1) <- nb
End
What is the value of cell (1,1)
Step by step
Solved in 2 steps with 1 images
- K Lold T T=T+(K-2)*L T=T- 10 T=0 T=T-10 K= 4, 8, 2 L=4, 3, -1 T=T+{K-2)*Lint FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
- if L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxint sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;
- int func(int a, int b) { return (a# hard-coded calls # hard-coded linescouple = NumCouple(4, 7)print(f"The couples minimum is {couple.minimum()}")print(f"The couples maximum is {couple.maximum()}")print(f"The couples product is {couple.product()}")thruple = NumThruple(3, 5, 2)print(f"The thruples minimum is {thruple.minimum()}")print(f"The thruples maximum is {thruple.maximum()}")print(f"The thruples product is {thruple.product()}")int x; X=-2; do { x++; cout0); cout<<"done"; O done O -2 done O -1 doneQ1 function myFunc() { let a = 10; if (true) { Q3 } } let a = 5; console.log(a); Q4 console.log(a); Q2 const square = num => num * num; console.log(square(3) + 5); myFunc(); let x = 30; let y "200"; console.log(x+y); const nums = [10, 20, 8, 17]; nums.filter(e=> e > 10); console.log(nums); Q5 const nums = [30, 35, 42, 20, 15]; console.log(nums.every (num => num > 20)); January 15-0 FAMAS oro ag -0 1 void printVerticalGraph(int nUnits) { 2 4 9 10 11 12 13 14 15 16 17 456 BARHEIDEN 18 19 20 21 22 23 24 25 26 27 int nRev; printf("%d\n", nUnits); while (nUnits>0){ nRev = getReverse (nUnits); // 1) Adjust nUnits ?? [Q1] ?? while (nRev>0){ nUnits *= 10; // 2) Condition to print * if(?? [Q2]??) { printf("*"); } // 3) Update for nUnits for * case ?? [Q3] ?? }else{ printf(" "); // 4) Update for nUnits for ?? [Q4]?? } // 5) Update to nRev ?? [Q5]?? printf("\n"); caseint j; switch (i) { case 0: j = 2*i; break; case 1: j = -i; break; default: j = -2*i; } What is j if i = 1? What is j if i = -1?SEE MORE QUESTIONS