AG° = 118.5 kJhnol Since AG has a positive value so this is not a spontaneous process. Exercise 3: Problem Solving 1. Predict the following reaction whether it is spontaneous or non- spontaneous. Show your complete solution 2 NaOH ( + CO2 ig b. 2Fe(s)+3 H2O) 2. Delermie the AS syteni given the reaction. CH12O6 +Ozg) Na2CO3 (6) +2 H2O Fe2O3 ) + 3 H2 (). a. →CO: Hz0) Tabel 1: Standard Free Energies of Formation

AG° = 118.5 kJhnol Since AG has a positive value so this is not a spontaneous process. Exercise 3: Problem Solving 1. Predict the following reaction whether it is spontaneous or non- spontaneous. Show your complete solution 2 NaOH ( + CO2 ig b. 2Fe(s)+3 H2O) 2. Delermie the AS syteni given the reaction. CH12O6 +Ozg) Na2CO3 (6) +2 H2O Fe2O3 ) + 3 H2 (). a. →CO: Hz0) Tabel 1: Standard Free Energies of Formation

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions

Section: Chapter Questions

Problem 116SCQ: Calculate rH for the reaction 2 C(s) + 3 H2(g) + O2(g) C2H5OH() given the information below. C(s)...

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M M (M Consider the reaction CH₂(g) + H₂O(g) 3H₂(g) + CO(g) Using the standard thermodynamic data in the tables linked above, calculate AG for this reaction at 298.15K if the pressure of each gas is 10.01 mm Hg. # 3 ANSWER: E D 00 C Submit Answer 4 000 000 R V kJ/mol Retry Entire Group 8 more group attempts remaining % 5 Use the References to access important values if needed for this question. T G Cengage Learning Cengage Technical Support B MacBook Pro Y H & 7 N U ►II J * 00 8 | M ( 9 K O 96 O L P V [ Previous Email Instructor WJ { [ + 11 ? 1 Next Save and Exit } 1 delet
Co2 (g) H20 (1) C,H12O6(s) 0:(@) Section 5.9 process: 6CO2(g) + 6H,O(1) → C,H12O6(s) +hther this problem: Co2 (g) H20 (1) C6H12O6(s) 0,6) T = 298 K -1273.1 ArH /kJ mol -393.5 -285.8 S/J mol K- CP.m/J mol K-I 0.0 209.2 2052 213.8 70.0 37.1 75.3 219.2 294 Calculate the entropy and enthalpy changes for this chemical system at T = 298.15 K and T = 365 K. Also calculate the entropy change of the surroundings and the universe at both temperatures.
A, Σ *00 urces V Hint Check Answer of 29 Use the data given here to calculate the values of AGin at 25 °C for the Compound rxn reaction described by the equation AG; (kJ/mol) +387.7 A +B C +613.4 B. +402.0 AGiXn %3D If AHxn and ASixn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions? The spontaneous reaction is entropy-driven to the left. O entropy-driven to the right. enthalpy-driven to the left. O enthalpy-driven to the right. Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry Publisher: University Science Boc 8:12 PM 口( 11/8/2021 PrtScr "R F12 Insert Delete F7 F8 F10 F11 Backspace 24 8 5. 7. R. B. Alt Ctri
Check below the correct expression for the thermodynamic equilibrium constant, K for the reaction: `eq' Zn(s) + 2HCI(aq) ? ZnCl,(aq) + 2H,(g) Checking an incorrect box brings negative points: [ZnCI,Jeg H2 Keg |2 eq eq eq K. `eq [HCIg Keq 2 ZnC [HCI eq OK = Ke = bə, %D K. (PHC)8q [znCl_Jo« PH, %3D eq eq 'eq None of the above
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Which of the following processes will have a positive AS°? 1st attempt Feedback See Periodic Table O See Hint Choose one or more: O C3H3 (g) + 50, (g) → 3CO,(g) +4H,0(1) Sweat evaporates O N,0,(g) → NO2(g) +NO,(g) Solid silver chloride dissolves in aqueous ammonia
Part A) Consider the reaction 4 HCl(g) + O2(g)----> 2 H2O(g) + 2 Cl2(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K.ANSWER: __________ Part B) Consider the reactionI2(g) + Cl2(g)---->2ICl(g)Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K.ANSWER:___________ Part C) Consider the reaction2H2O2(l)----->2H2O(l) + O2(g)Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K.ANSWER:__________
A reaction that, at 25°C, has AG = -1kJ/mol is spontaneous. In order for the reaction to become nonspontaneous at 37°C, the change in enthalpy for the reaction would have to be The change in entropy for the reaction would have to be Submit Answer Try Another Version 4 item attempts remaining
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abbo c Replace ab x, x A A. 1 Normal 1 No Spac. 1 Heading 1 1 Heading 2 - Dictate Sensitive A Select v Font Paragraph Styles Editing Voice Sensitivit 3. For a particular reaction, AH=-99,84 kJ/mol, and AS=-16.80 J/(mol·K). Calculate AG for this reaction at 298 K. Answer: Explanation: English (United States) D. Focus re to search 61%