a. Determine the COD (mg/L) of 1% acetate based on an aqueous solution. Use necessary information from the following half-cell reaction for acetate Reaction number Acetate: 18. ICO, +HCO3 + H+ + e Half-reaction =CH,COO + H₂O AG (W), kJ per electron equivalent 27.68

Chemistry: Principles and Reactions
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Chapter17: Electrochemistry
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Problem 73QAP: Consider the reaction below at 25°C: 2MnO4(aq)+16H+(aq)+10Br(aq)2Mn2+(aq)+5Br2(l)+8H2O Use Table...
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a. Determine the COD (mg/L) of 1% acetate based on an aqueous solution. Use necessary
information from the following half-cell reaction for acetate
Reaction
number
Acetate:
18.
ICO, +HCO3 + H+ + e
Half-reaction
=CH,COO + H₂O
AG (W),
kJ per electron
equivalent
27.68
Transcribed Image Text:a. Determine the COD (mg/L) of 1% acetate based on an aqueous solution. Use necessary information from the following half-cell reaction for acetate Reaction number Acetate: 18. ICO, +HCO3 + H+ + e Half-reaction =CH,COO + H₂O AG (W), kJ per electron equivalent 27.68
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