A system with a 16M x 8 main memory has an 8G x 4K virtual memory and will require ___ bits for each virtual address, ___ bits for each physical address, and ___ bits for the offset in both addresses.
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A system with a 16M x 8 main memory has an 8G x 4K virtual memory and will require ___ bits for each virtual address, ___ bits for each physical address, and ___ bits for the offset in both addresses.
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- Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one cycle to complete, assuming zero wait state memory accesses. Processor C is a CISC processor with a 1.8 GHz clock rate. The average simple instruction requires one cycle to complete, assuming zero wait state memory accesses. The average complex instruction requires two cycles to complete, assuming zero wait state memory accesses. Processor R can’t directly implement the complex processing instructions of Processor C. Executing an equivalent set of simple instructions requires an average of three cycles to complete, assuming zero wait state memory accesses. Program S contains nothing but simple instructions. Program C executes 70% simple instructions and 30% complex instructions. Which processor will execute program S more quickly? Which processor will execute program C more quickly? At what percentage of complex instructions will the performance of the two processors be equal?Assuming memory frame size = process page size = 1024, what physical address will logical address 2076 of process P2 be mapped to? a. 1052 b. 1024 c. 2076 d. more information needed e. 2048Q: A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses direct mapping with a block size of 4 words. i) How many bits are there in the tag, index, block & words fields of the address formats.ii) How many bits are there in each word of cache? iii) How many blocks can the cache accommodate? Note: this question is related from computer architecture subject kindly solved this correctly and completly.
- Computer Science Please explain in detail the steps in translating a 24 bit virtual address to a 32 bit physical address in a system with a two-level page table where the page directory is 32 entries and the size of each page table is 512 entries. Include the length of the bit fields that make up the virtual address and the physical address.A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses direct mapping with a block size of 4 words.i) How many bits are there in the tag, index, block & words fields of the address formats.ii) How many bits are there in each word of cache?iii) How many blocks can the cache accommodate?Please help me in this question: 22/ A shared memory multiprocessor (SMP) has a __________ . a. single physical address space across all processors b. single virtual address space across all processors c. separate physical address space for each processor that can be shared d. single cache for all processors Thank you.
- please help me. thank you Currently, in a PC equipped with 8 GByte of main memory, the CPU actually supports only 32-bit (4 GB) physical address space, but when the 40-bit (1 TB) virtual address space is supported for executing large-scale programs. , When the page size is 2KByte and 4 bytes per page table entry are used. 1) How many bytes is the sige of the page table allocated per process? 2) Explain why this processor configuration is practical. 3) How do I change which of the parameters given in the problem for this processor to be practical?1- define the following:Clock rateInstruction setBandwidthParallelism.CMOS TechnologyEmbedded systems1)What are the differences between RAM and ROM and what is the control unit in 8086 and its function?2_what is the ALU and its function?5- What physical address is represented by: (a)4370:561EH (b) 7A32:0028HMake a distinction between the logical address space and the physical address space.
- What is the difference between a physical and virtual address? Please contrast and clarify.REAL MODE MEMORY ADDRESSING 1. In the real mode, show the starting and ending address of the segment located by the following segment register values (in hex): a) SR= DC28b) SR=FA91 2. Find the memory location addressed by the microprocessor, when operated in the real mode, for the following segment register and 80286 register combinations: a) DS=8EBC & DX=A3D7b) CS=DCAF & IP=FAC8 Appreciate your help. Thanks!An operating system designed for an embedded system application needs to manage a process of size 512KB with a page size of 8KB. If the memory size is 256KB then answer the following questions - a) Determine the minimum number of bits required to manage the logical address space. b) Determine the minimum number of bits required to manage the physical address space.