A student performed a chromatography experiment to determine the Rf value of an unknown amino acid. The distances traveled by the amino acid and the solvent line were 3.0 cm and 8.5 cm, respectively. What is the R₁ value for this amino acid? 0.3 cm 0.35 1.8 O 5.5 0.85 cm 0.65 2.8
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- 1) a)What is affinity chromatography and what is it used for? b) A drug called Bamlanivimab is used to treat infections with SARS-CoV-2 (Covid-19).This drug was developed by isolating antibodies from the serum of a patient who recovered from Covid-19.What is possibly on the stationary phase in a column used to isolate antibodies to SARS-CoV-2? How are the antibodies eluted off the column to isolate them for drug development?1) Study the chromatograph (below) of a mixture of Compounds A and B, run on the GCs in the teaching labs at CU Boulder. Compound A has the shorter retention time. STAAT 61 1.11 227 RT TYPE AREA XXXX XXXX XXXX AREAS 0.009 55874 44.117 ARIHT 0.61 XX XX XX 1.11 2.27 XX XX XX TOTAL AREA=XX MUL FACTOR=XX 1. What is the retention time of compound A? Compound B? 2. Which compound is present in a larger amount? 3. Which compound has the lower boiling point? 4. What would happen to the retention times of compounds A and B if the column temperature were raised? 5. You suspect that compound B is octane. What can you do to provide supporting evidence for this hypothesis?You run the chromatography system with paper as the stationary phase and 70% isopropanol as the mobile phase. You determine the Rf of a polar analyte to be 0.40. If you use 100% isopropanol (a less polar solvent) instead of isopropanol as the mobile phase what would you expect to happen to the Rf value? No value effect on Rf higher lower could be higher or lower
- A student researcher performed a chromatographic separation of caffeine and aspartame. The retention time for caffeine, tc, was found to be 209.6 s with a baseline peak width, w., of 14.4 s. The retention time for aspartame, ta, was 260.0 s with a baseline peak width, wa, of 21.2 s. The retention time for the unretained solvent methanol was 49.2 s. Calculate the average plate height, H, in micrometers for this separation, given that it was performed on a 22.1 cm long column. H = um %3D Calculate the resolution, R, for this separation using the widths of the peaks. R = Calculate the resolution if the number of theoretical plates were to increase by a factor of 2. R2N =2. What are mobile and Stationary phases in a chromatogram? Site their nature.In molecular exclusion (size exclusion) chromatography, the molecules have the longest retention times. a) the larger molecules b) the smaller molecules
- Analysis of an unknown plant extract yield two peaks X and Y in a chromatogram, 15.65 and 17.03 min respectively in a 30.0 cm column. The peak base width for X is 1.06 and 1.15 for Y. The average number of plates in the column isuse the following chromatogram and table as your data. VWD: Sgrad A 284 nm Retention Time 40- -40 20 20 5 10 15 20 25 30 35 Minuteo VWD: Signal A, 284 nm Retention Area Identity Time (min) 7.867 3214697 Vitamin A 8.493 15687 19.410 140354 19.710 64346 20.803 884315 Vitamin E 21.640 36745 22.100 63054 8.403 L98 ÞI 20.803 ; 84年 81Q24) Consider the following data obtained from the size exclusion chromatography of polypropylene, which was made from propylene of molecular weight 42.08 g/mol. S.No. Number of Molecular Weight Molecules Range (g/mol) 5 8,000 - 16,000 16 16,000 - 24.000 3. 24 24,000 - 32,000 4 28 32,000 - 40,000 5 20 40,000 - 48,000 48,000 – 56,000 From the above data, determine a) Number average molecular weight (M). b) Weight average molecular weight ( Mw). c) Degree of polymerization (DP)
- A student researcher performed a chromatographic separation of caffeine and aspartame. The retention time for caffeine, te, was found to be 200.8 s with a baseline peak width, we, of 16.1 s. The retention time for aspartame, ta, was 258.7 s with a baseline peak width, wa, of 20.6 s. The retention time for the unretained solvent methanol was 44.2 s. Calculate the average plate height, H, in micrometers for this separation, given that it was performed on a 22.1 cm long column. H = Calculate the resolution, R, for this separation using the widths of the peaks. R = 88.2 R₂5N = 3.16 Calculate the resolution if the number of theoretical plates were to increase by a factor of 2.5. 3.533 Incorrect μmConsider the peaks for heptane (14.56 min) and p-difluorobenzene (14.77 min) in the chromatogram. The column is 30.0 m long. (a) Measure w1/2 for each peak and calculate the number of plates and the plate height for each. (b) From w1/2, compute w for each peak and find the resolution between the two peaks.In normal-phase HPLC chromatography, the stationary phase is polar and the mobile phase is nonpolar. In the reversed phase we have just the opposite; the stationary phase is nonpolar and the mobile phase is polar. Describe molecules in which move faster or slower in each case.