A student drew a circle and two secant segments. He concluded that If PQ PS, then QR ST.Do you agree with the student's condusion? Why or why not? Complete the explanation. = QR V. Since PR PQ = PT PS by the Given: PQ PS.Then PQ (select) PR = PQ + QR and PT = PS +ST,PQ +QR =(select) v.Since PQ = PS, QR = (select) .Therefore, QR (select) v congruent to ST.So, I (select) v v,PR PS = PT PS, and so PR = (select) v. Since %3D %3D %3D %3D

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.3: Rules For Addition
Problem 7P
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A student drewa circle and two secant segments. He concluded that If PQ PS, then QR ST.Do you
agree with the student's conduslon? Why or why not? Complete the explanation.
P.
Since PR PQ = PT PS by the
v,PR PS PT PS, and so PR = (select) . Since
Given: PQ PS.Then PQ= QR v
(select)
PR = PQ+QR and PT = PS+ST,PQ +QR = (select) v. Since PQ = PS,QR = (select) v.Therefore,
QR (select) v congruent to ST. So, I (select)
%3D
%3D
Transcribed Image Text:Question Example Step by Step A student drewa circle and two secant segments. He concluded that If PQ PS, then QR ST.Do you agree with the student's conduslon? Why or why not? Complete the explanation. P. Since PR PQ = PT PS by the v,PR PS PT PS, and so PR = (select) . Since Given: PQ PS.Then PQ= QR v (select) PR = PQ+QR and PT = PS+ST,PQ +QR = (select) v. Since PQ = PS,QR = (select) v.Therefore, QR (select) v congruent to ST. So, I (select) %3D %3D
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