A Sodium Chloride (0.1920g) NaCl was assayed using volhard Method, using 52mL of 0.0975N AgN03 and 12.3 mL of 0.1192Ammonium thioscyanate. Calculate the sample in %.
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- Precipitimetry The chloride in a 4.321-g food sample was precipitated through the addition of 50.00 mL of a standard AgNO3 solution (10.00 mL AgNO3 = 11.22 mL KSCN). The precipitate was coated with nitrobenzene and the mixture was diluted to 250.0 mL. A 50.00 mL aliquot was taken from the diluted solution and required 4.56 mL back titration with a %3D standard KSCN solution (22.33 mL KSCN = 0.9758 g AgNO3). %3D Formula Masses: AgNO3 = 169.87; CI = 35.45 Calculate the following: 1. Molar concentration of KSCN solution M %3D 2. Molar concentration of AgNO3 solution M %3D 3. % (w/w) chloride in the original sample =(3) In a titration, the % analyte is computed from the following equation: Vol (titrant) x M (titrant) x MW (analyte) % analyte = x 100 Weight (sample) Calculate the absolute error in the % analyte from the following data. Vol (titrant)= 38.04 t 0.02 ml M (titrant) MW (analyte) = 74.116 t 0.005 mg/mmol Wt (sample) = 800.0 ± 0.2 mg = 0.1137 ± 0.0003 mmol/ml %3!You are preparing a 100.0 mL standard solution needed for titration analysis. The NaOH (40 g/mol) pellets are measured to be 0.5341 g in a balance with acceptable uncertainty of +0.001 g. Mass of the pellets is recorded after taring the container. The pellets are put in a beaker and added with 50 ml distilled water measured by a graduated cylinder. The solution is then quantitatively transferred to a 100-mL volumetric flask with uncertainty of ±0.08 mL and diluted to a 100-mL mark. What is the concentration (M) of the solution and estimate its uncertainty by propagation? Assumption: There is no uncertainty in molar mass. Express your answer as C+/- u M.
- An impure sample of calcium carbonate with a mass of 7.95 g was reacted with 50.00 cm3 of 1.00 mol dm hydrochloric acid (an excess). The resulling solution was transferred to a volumetric flask and titrated with 11.10cm3 of 0.300 mol dm-3 sodium hydroxide solution. Determine the percentage purity by mass of the calcium carbonate sample.CaCO3 + HCl -> CaCl2 + H2O + CO2 HCl + NaOH -> NaCl +H2O a. Determine how many moles of hydrochloric acid were used.b. Determine how many moles of excess HCI was titratedc. Determine how much in moles calcium carbonate present in the sample.d. Calculate the mass of calcium carbonate presente. Determine the percentwge calcium carbonate is in the sample.A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 ml, aliquot was titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Another 20 mL aliquot was titrated to the BCG endpoint, using up 18.87 mL of titrant in the process. Identify the alkali components and their percent weight.A 20.330 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 74.044 g of water. A 10.245 g aliquot of this solution is then titrated with 0.1074 M HCl. It required 29.47 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH, in the aqueous waste. wt% NH3 = APR 9 $ 4 R dº 10 % . 5 Search or type URL n T tv < 60 ♫ MacBook Pro A Y & N 7 907 U * 8 00 + I A ( 9 © | O - O W P J { + [ % ] delete
- : Egbabl Qe A Solution is Prefared Tby dissdlving 6g AgNoz ina 250-ml Volumetric Hask and diliting the molaurity of the Silver nityate Solution How to Volume. alculute Many millimoles Ag No3. Were dissalved7 twt Ag Noz 169-9HatA 25.00mL wastewater sample was analyzed for its Mg2+ content using a standard gravimetric method. the sample was diluted to 3.00L and an 11.00mL aliquot was treated to precipitate magnesium as MgNH4PO4.6H2O using (NH4)2HPO4 as the precipitating agent. the precipitate was then filtered, washed, dried, and ignited resulting in a 0.1325mg Mg2P2O7 residue. How much Mg (in ppm) is present in the original sampleMass solute needed to prepare 0.500L of 0.2 M NaCO3 from a solid NaCO3 with a purity of 92.0wt%
- Q3/ A) 0.63 g of a sample containing Na,CO3, NaHCO, and inert impurities is titrated with 0.2 M HCI, requiring 17.2 mL to reach the phenolphthalein end point and a total of 43.5 mL to reach the modified methyl orange end point, How many grams NazCO3 and NaHCO, are in the mixture?The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? OA. Solution A: 0.123 Solution B: 0.463 O B. Solution A: 0.463 Solution B: 0.234 O C. Solution A: 0.123 Solution B: 0.234 O D. Solution A: 0.234 Solution B: 0.463The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463