A series RLC circuit has a resistance of 7.5 , a capacitance of 10-2 F, an inductance of 1/6 H, and an applied voltage E = 12 V. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system. 1. What is the simplified linear ODE with constant coefficient from the problem? A. (D² +42D + 600)I = 0 (D² +45D + 600)I = 0 B. (D² +45D + 40/3)] = 0 None of the choices 2. What is the equation to solve for I of the system? 5√15 A. I= e-45t B₁ cos 5√15 2 15t) 5√15 B. 1 = e 2 B₁ cos 2 B. 45 1=e 2 3. What is the value of constant B₁? A. -72 B. 0 4. What is the value of I'(0)? A. -72 B. 0 -t + B₂ sin -t + B₂ sin. 45 2 COS C. D. t C. D. C. D. 45 1= e 2 B₁ cos 5. What is the final equation to solve for the subsequent current of the system? 48√15 5√15 45, (48√15) 5√15 A. 1 = e-45t C. sin t 25 2 25 2 5√15 (48√15) 45 COS t 25 2 D. None of the choices 45 72 C. 45 D. 72 5√15 5√15 t + B₂ sin 2 2 1=e=2 None of the choices

Delmar's Standard Textbook Of Electricity
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Chapter20: Capacitance In Ac Circuits
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A series RLC circuit has a resistance of 7.5 , a capacitance of 10-2 F, an inductance of 1/6 H, and
an applied voltage E = 12 V. Assuming no initial current and charge when voltage is first applied,
find the subsequent current in the system.
1. What is the simplified linear ODE with constant coefficient from the problem?
A. (D² +42D + 600)I = 0
(D² +45D + 600)I = 0
None of the choices
B. (D² +45D + 40/3)] = 0
2. What is the equation to solve for I of the system?
5√15
A. I= e-45t B₁ cos
5√15
2
15t)
5√15
B. I= e 2
B₁ cos
2
B.
45
1=e
2
3. What is the value of constant B₁?
A.
-72
B.
0
4. What is the value of I'(0)?
A.
-72
B.
0
-t + B₂ sin
-t + B₂ sin.
COS
45
2
2
45
COS t
2
C.
D.
t
C.
C.
D.
5. What is the final equation to solve for the subsequent current of the system?
48√15
5√15
A.
1 = e-45t
C.
25
5√15 (48√15
25
1=e=2 B₁ cos
D. None of the choices
45
45
72
C.
45
D. 72
D.
5√15
2
1= e 2¹
45, (48√15) 5√15
sin
t
25
2
t + B₂ sin
None of the choices
5√15
2
Transcribed Image Text:A series RLC circuit has a resistance of 7.5 , a capacitance of 10-2 F, an inductance of 1/6 H, and an applied voltage E = 12 V. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system. 1. What is the simplified linear ODE with constant coefficient from the problem? A. (D² +42D + 600)I = 0 (D² +45D + 600)I = 0 None of the choices B. (D² +45D + 40/3)] = 0 2. What is the equation to solve for I of the system? 5√15 A. I= e-45t B₁ cos 5√15 2 15t) 5√15 B. I= e 2 B₁ cos 2 B. 45 1=e 2 3. What is the value of constant B₁? A. -72 B. 0 4. What is the value of I'(0)? A. -72 B. 0 -t + B₂ sin -t + B₂ sin. COS 45 2 2 45 COS t 2 C. D. t C. C. D. 5. What is the final equation to solve for the subsequent current of the system? 48√15 5√15 A. 1 = e-45t C. 25 5√15 (48√15 25 1=e=2 B₁ cos D. None of the choices 45 45 72 C. 45 D. 72 D. 5√15 2 1= e 2¹ 45, (48√15) 5√15 sin t 25 2 t + B₂ sin None of the choices 5√15 2
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