A proton is accelerated through a potential difference of 1200 V. What is the proton's speed at the end? (mp 1.67 x 10-27 kg) O4.8 x 10^5 m/s 3.4 x 10^5 m/s O 1.2 x 10^7 m/s O 3.3 x 10^6 m/s 4.1 x 10^6 m/s

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
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A proton is accelerated through a potential difference of 1200 V. What is the proton's speed at the end? (mp
1.67 x 10-27 kg)
4.8 x 10^5 m/s
3.4 x 10^5 m/s
O 1.2 x 10^7 m/s
O 3.3 x 10^6 m/s
4.1 x 10^6 m/s
=
Transcribed Image Text:A proton is accelerated through a potential difference of 1200 V. What is the proton's speed at the end? (mp 1.67 x 10-27 kg) 4.8 x 10^5 m/s 3.4 x 10^5 m/s O 1.2 x 10^7 m/s O 3.3 x 10^6 m/s 4.1 x 10^6 m/s =
Expert Solution
Step 1

Given

Potential difference = V = 1200 volts

mass of proton = mp = 1.67 × 10-27 kg

We have to calculate the speed of the proton at the end.

 

 

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