A physician wants to see if there was a difference in the average smokers' daily cigarette consumption after wearing a nicotine patch. The physician set up a study to track daily smoking consumption. In the study, the patients were given a placebo patch that did not contain nicotine for 4 weeks, then a nicotine patch for the following 4 weeks. Test to see if there was a difference in the average smoker's daily cigarette consumption using α = 0.01. The hypotheses are: H0 : μD = 0 H1 : μD ≠ 0 t-Test: Paired Two Sample for Means Placebo Nicotine Mean 18.75 12.3125 Variance 66.599 34.6667 Observations 16 16 Pearson Correlation 0.6105 Hypothesized Mean Difference 0 df 15 t Stat 3.5481 P(T<=t) one-tail 0.0126 t Critical one-tail 2.6025 P(T<=t) two-tail 0.0252 t Critical two-tail 2.9467 What is the correct p-value? Question 1 options: 0.6105 2.6025 2.9467 0.0126 0.0252

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 15PPS
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A physician wants to see if there was a difference in the average smokers' daily cigarette consumption after wearing a nicotine patch. The physician set up a study to track daily smoking consumption. In the study, the patients were given a placebo patch that did not contain nicotine for 4 weeks, then a nicotine patch for the following 4 weeks. Test to see if there was a difference in the average smoker's daily cigarette consumption using α = 0.01. The hypotheses are:

H0 : μ= 0

H1 : μ≠ 0

t-Test: Paired Two Sample for Means

 

 

 

 

Placebo

Nicotine

Mean

18.75

12.3125

Variance

66.599

34.6667

Observations

16

16

Pearson Correlation

0.6105

 

Hypothesized Mean Difference

0

 

df

15

 

t Stat

3.5481

 

P(T<=t) one-tail

0.0126

 

t Critical one-tail

2.6025

 

P(T<=t) two-tail

0.0252

 

t Critical two-tail

2.9467

 

 

What is the correct p-value?

 

Question 1 options:

 

0.6105

 

2.6025

 

2.9467

 

0.0126

 

0.0252

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