A large ear of corn has a total of 4333 grains including 271 purple smooth,73 purple and shrunken, 63 yellow and smooth, and 26 yellow shrunken a) What is the Chi-square value? b) Make a hypothesis.
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A large ear of corn has a total of 4333 grains including 271 purple smooth,73 purple and shrunken, 63 yellow and smooth, and 26 yellow shrunken
a) What is the Chi-square value?
b) Make a hypothesis.
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- A packing plant fills bags with cement. The weight X kg of a bag of cement can be modelled by a Normal distribution with mean 50 kg and standard deviation of 2kg. a) If a bag is selected is at random, find the probability that the weight of the bag is greater than 55 kg. b) If three bags are selected at random, find the probability that 2 bags weigh more than 55 kg. c) Compute the probability in part a using RStudio.What does the graph imply?German measles results from an infection of the rubella virus, which can cause a multitude of health problems in newborns. What conclusions can you reach from a nucleic acid analysis of the virus that reveals an A + G/U + C ratio of 1.13?
- An analysis is performed to determine the proportions of each of the four nucleotide bases in the DNA of several tissue samples from various species. The results appear in the table. Human Chicken Yeast E. coli % Adenine % Guanine (A) (G) 31 20 28 21 32 18 26 25 % Thymine % Cytosine (T) 30 29 33 24 Which conclusions can be drawn from this data? (C) 19 22 17 25 The proportion of G is roughly equal to the proportion of C. The proportion of A is roughly equal to the proportion of T. The proportion of pyrimidines is roughly equal to the proportion of purines. The proportion of A-T base pairs is roughly equal to the proportion of G-C base pairs.how did we get the number 1x10^6？and 3.98x10^-8？explain？？where these number come from？Baker's yeast, Saccharomyces cerevisiae, is a single-celled, diploid fungus (which is, of course, a eukaryote, that is capable of both meiosis and sexual reproduction). Wild type yeast can normally grow on solid or liquid minimal medium; you isolate three mutant strains which are no longer capable of growing on minimal medium alone, however, they can grow on medium supplemented with adenine. All three yeast strains are homozygous for the underlying alleles. When you cross mutant strain 1 and mutant strain 2, the offspring cannot grow on minimal medium alone and require adenine supplementation; when you cross mutant strain 1 and mutant strain 3, the offspring can grow on minimal medium alone and do not require adenine. A. What conclusions can you make about the alleles of mutant strains 1, 2, and 3 and their relationships with each other? B. What phenomenon is occurring in the cross between mutant strains 1 and 3? After crossing the F1 generation of the cross between mutant strains 1…
- Baker's yeast, Saccharomyces cerevisiae, is a single-celled, diploid fungus (which is, of course, a eukaryote, that is capable of both meiosis and sexual reproduction). Wild type yeast can normally grow on solid or liquid minimal medium; you isolate three mutant strains which are no longer capable of growing on minimal medium alone, however, they can grow on medium supplemented with adenine. All three yeast strains are homozygous for the underlying alleles. When you cross mutant strain 1 and mutant strain 2, the offspring cannot grow on minimal medium alone and require adenine supplementation; when you cross mutant strain 1 and mutant strain 3, the offspring can grow on minimal medium alone and do not require adenine. After crossing the F1 generation of the cross between mutant strains 1 and 3, you count and determine the phenotypes of 1,000 colonies (here a colony is equivalent to an individual): 563 colonies that can grow on minimal medium alone; 437 colonies that require adenine…Baker's yeast, Saccharomyces cerevisiae, is a single-celled, diploid fungus (which is, of course, a eukaryote, that is capable of both meiosis and sexual reproduction). Wild type yeast can normally grow on solid or liquid minimal medium; you isolate three mutant strains which are no longer capable of growing on minimal medium alone, however, they can grow on medium supplemented with adenine. All three yeast strains are homozygous for the underlying alleles. When you cross mutant strain 1 and mutant strain 2, the offspring cannot grow on minimal medium alone and require adenine supplementation; when you cross mutant strain 1 and mutant strain 3, the offspring can grow on minimal medium alone and do not require adenine. A. What conclusions can you make about the alleles of mutant strains 1, 2, and 3 and their relationships with each other? B. What phenomenon is occurring in the cross between mutant strains 1 and 3?Which one of these is correct ? And why are the rest incorrect?
- Can someone explain why those values were chosen to be divided by the total? I thought it was the four smallest amounts, so I would have done 3+64+67++7/1600. Can someone explain why that would have been wrongFor another project, you designed primers 1 and 2 with the sequences shown below. Your lab partner suggests you calculate the primer melting temperatures (Tm) using the formula: Tm = [(A+T) x 2°C] + [(G+C) x 4°C]. Calculate the Tm for Primers 1 and 2 and give your answers in the boxes provided below. You must give your answer as a whole number (no decimal places). Units (°C) are already shown so must not be included in your answer. Primer 1 (forward): 5' TTCGTCTGGTGAACTCAG 3' °C Primer 2 (reverse): 5' CAGGGTATGTCCGTATAT 3' °Cif one base pair of DNA weighs 650 kDA, how much does the entire human genome with 3.3x109 weigh? How many molecules of pentanoic acid are in 3.20 moles of pentanoic acid? How many kilometers per hour are there in 1.98m/s?