A human cannon ball is fired at an angle of 60 degrees and speed of 25m/s. If the net is located 35 meters in front of the human cannon, how high in the air should the net be placed so the human lands in the center of it. Please Use the equations provided Equations:Vector components, standard Cartesian plane:Vx= V cos 8Vy = V sin 0Constant linear acceleration:V = Vo + atProjectile motion:X = Xo + VoxtRotational motion:0 = s/r@= @o + atFrictional force:w = v/rNewton's Second Law of motion:Centripetal force:Use gd = do + Vot + ½ at²Gravitational force, or weight:=Vx² + Vy² = V²y = yo + Voy - 1/2 gt²360⁰ = 2n radiansa = aT/r000+ wot + ½ at²tan 8 = Vy/Vxv² = vo² + 2a(d-do)Vy = Voy -gtac = v²/r = rw²w² = wo² + 2a(0 - 0)ΣF = maFg = mgFf = µFnFc = mv²/r10.0 m/s² for the acceleration due to gravity near the surface of the earth.

Name: A human cannon ball is fired at an angle of 60 degrees and speed of 25
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: A human cannon ball is fired at an angle of 60 degrees and speed of 25m/s. If the net is located 35 meters in front of the human cannon, how high in the air should the net be placed so the human lands in the center of it. Please Use the equations pro