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- A misaligned crossover between two homologous chromosomes usually results in:Duchenne’s muscular dystrophy (DMD) is an X-linked disease that causes progressive muscle weakness and is often fatal. “XD” represents the wild type allele, and “Xd,” the mutant allele. Jonah is XDXd Y and his brother Pete is Xd Y. Jonah and Pete BOTH have DMD of equal severity and phenotypes. You might have thought Jonah’s DMD would be less severe given his genotype. To better understand the situation, you investigate Jonah’s Xist chromosome region in his defective muscle cells. Which of the following is consistent with his phenotype? (Select all that apply.) The Xd-containing chromosome is inactive in defective muscle cells. The XD-containing chromosome has a methylated Xist promoter. The XD-containing chromosome has an unmethylated Xist promoter. The Xd-containing chromosome is active in defective muscle cells.How many Y chromosomes are there in an individual with Klinefelter syndrome? 0 1 2 3 4 CHOOSE ONE
- An individual with 46, XX genotype is diagnosed with Duchenne-type Muscular Dystrophy, a recessive X-linked disorder. Genetic tests confirm that this individual is a heterozygote for this disorder. Briefly, but specifically, explain how it’s possible that they are showing symptoms of this disorder.Two people are planning to have children together. Each person is heterozygous for the gene “A”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer).In Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vg
- An allele that is not expressed in the heterozygous condition isIn a parental cross of a autosomal dominant homozygous lethal disease trait, where the father is affected and mother unaffected, 50% of offspring will have disease phenotype and 50% will have the wild type phenotype. In f1 cross between affected male and unaffected female, the expected proportions of the disease phenotype and the wild type phenotype in the f2 generation are:A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?
- TTGG ttgg F1 TG tg F2 TtGg Which types of genotypes are represented in F1 and F2 in the above figure, respectively? heterozygous and heterozygous heterozygous and homozygous homozygous and heterozygous homozygous and homozygousTwo parents have the following genotypes. FF and Ff. Which of the following genotypes is not possible for their children? - FF -Ff -ffIf two individuals are crossed (RrYy x RrYy), what percentage of their offspring will display the R_yy phenotype? (the _ could be either R or r, it would not affect the phenotype).