A geneticist is using a three-point testeross to map three linked Drosophila recessive mutations called a, b, and c, where a is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the Fi progeny to anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map distance between b and c. Testcross progeny phenotype Number map distance: m. u. curved 281 anomalous, buckled 279 wild type anamalous, buckled, curved buckled, curved 133 anomalous 127 86 anomalous, curved buckled 84

Biology: The Dynamic Science (MindTap Course List)
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Chapter13: Genes, Chromosomes, And Human Genetics
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Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...
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Question 16 of 18
A geneticist is using a three-point testeross to map three linked Drosophila recessive mutations called a, b, and c, where a
is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first
crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the Fi progeny to
anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map
distance between b and c.
Testcross progeny phenotype
Number
map distance:
m. u.
curved
281
anomalous, buckled
279
wild type
4
6.
anamalous, buckled, curved
buckled, curved
133
anomalous
127
86
anomalous, curved
buckled
84
Transcribed Image Text:Question 16 of 18 A geneticist is using a three-point testeross to map three linked Drosophila recessive mutations called a, b, and c, where a is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the Fi progeny to anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map distance between b and c. Testcross progeny phenotype Number map distance: m. u. curved 281 anomalous, buckled 279 wild type 4 6. anamalous, buckled, curved buckled, curved 133 anomalous 127 86 anomalous, curved buckled 84
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