A drug manufacturer claims that fewer than 10% of its patients experience nausea. A significance test is conducted with a Null Hypothesis of p = 0.1 versus an Alternative Hypothesis that p < 0.1 at 5%. What is a consequence of a Type II error in this context?
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- What is meant by the sample space of an experiment?An RA at the University of Baltimore has concluded that the difference between the mean GPA scores of Senior and junior is statistically significant, when in fact the null hypothesis of no difference is true. What type of error has he committed?A type 2 error occurs when a treatment actually does have an effect on the scores but the effect was not large enough to reject the bill hypothesis. True or false?
- An independent measures research study with n=5 participants in each treatment produces sample variances of 8 and 10, and a 2-point difference between the two treatment means. What is the value of Cohens d?An automobile manufacturer claims that their van has a 46 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this van. After testing 61 vans they found a mean MPG of 46.1 with a variance of 6.76 MPG. Is there sufficient evidence at the 0.01 level that the vans outperform the manufacturer's MPG rating? State the null and alternative hypotheses for the above scenario.For an ANOVA comparing three treatment conditions, what is stated by the null hypothesis (H0)? a. There are no differences between any of the population means. b. At least one of the three population means is different from another mean. c. All three of the population means are different from each other. d. None of the other choices is correct.
- For a repeated-measures study, a small variance for the difference scores indicates that the treatment has little or no effect. True or False?Annie is concerned over a report that "a woman over age 4040 has a better chance of being killed by a terrorist than of getting married." A study found that the likelihood of marriage for a never-previously-wed, 4040-year-old university-educated American woman was 2.8%2.8%. To demonstrate that this percentage is too small, Annie uses her resources at the Baltimore Sun to conduct a simple random sample of 513513 never-previously-wed, university-educated, American women who were single at the beginning of their 4040s and who are now 4545. Of these women, 2323 report now being married. Does this evidence support Annie’s claim, at the 0.050.05 level of significance, that the chances of getting married for this group is greater than 2.8%2.8%? Step 3 of 3 : Draw a conclusion and interpret the decision.Independent random samples of 32 people living on the west side of a city and 30 people living on the east side of a city were taken to determine if the income levels of west side residents are significantly different from the income levels of east side residents. Given the testing statistics below, determine if the data provides sufficient evidence to conclude that the income levels of west side residents are significantly different from the income levels of east side residents, at the 2% significance level. H0:μw=μeHa:μw≠μe t0=2.364 t0.01=±2.099 Select the correct answer below: No; the test statistic is not between the critical values. No; the test statistic is between the critical values. Yes; the test statistic is not between the critical values. Yes; the test statistic is between the critical values.