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a) Consider the coordinate transformation given by x = 3u+2 v vy 13 ³‚y = 2 u-3 v Compute the absolute value of the Jacobian of x, y with respect to u, v J = 13/169 Your last answer was interpreted as follows: 13 169 13 b) Let be the second quadrant of the xy-plane, i.e. the region described by the inequalities x ≤ 0, y ≥ 0. Using the coordinate transform from part a evaluate √ √ e−1 (2x-3y² dxdy = Here t is a positive constant.

a) Consider the coordinate transformation given by x = 3u+2 v vy 13 ³‚y = 2 u-3 v Compute the absolute value of the Jacobian of x, y with respect to u, v J = 13/169 Your last answer was interpreted as follows: 13 169 13 b) Let be the second quadrant of the xy-plane, i.e. the region described by the inequalities x ≤ 0, y ≥ 0. Using the coordinate transform from part a evaluate √ √ e−1 (2x-3y² dxdy = Here t is a positive constant.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 93E
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a) Consider the coordinate transformation given by x = 3u+2 v 13 y = 2 u-3 v Compute the absolute value of the Jacobian of x, y with respect to u, v J = 13/169 Your last answer was interpreted as follows: 13 169 13 b) Let be the second quadrant of the xy-plane, i.e. the region described by the inequalities x ≤ 0, y ≥ 0. Using the coordinate transform from part a evaluate Se−1 (2x-3y² dxdy = Here is a positive constant.
Transcribed Image Text:a) Consider the coordinate transformation given by x = 3u+2 v 13 y = 2 u-3 v Compute the absolute value of the Jacobian of x, y with respect to u, v J = 13/169 Your last answer was interpreted as follows: 13 169 13 b) Let be the second quadrant of the xy-plane, i.e. the region described by the inequalities x ≤ 0, y ≥ 0. Using the coordinate transform from part a evaluate Se−1 (2x-3y² dxdy = Here is a positive constant.
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