A compound has a formula of C19H16- Five signals appear in its 1°C NMR spectrum-one at 57 ppm and the remainingfour between 126 and 144 ppm. In its 'H NMR spectrum, an unresolved multiplet (15 H) appears between 6.9 and7.44 ppm and a singlet (1 H) appears at 5.5 ppm. What is the structure of this compound?

Degree of unsaturation It is the number of double bonds or number of rings present in a compound The…

Answered: A compound has a formula of C19H16-…

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter21: Benzene And The Concept Of Aromaticity

Section: Chapter Questions

Problem 21.29P

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Propose a structural formula for each compound consistent with its 1H-NMR and 13C-NMR spectra. (a) C5H10O2 (b) C7H14O2 (c) C6 H12O2 (d) C7H12O4 (e) C4H7ClO2 (f) C4H6O2
The 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.
The 1H-NMR spectrum of Compound C shows five signals – δ 2.38 (1H, dt), 2.72 (1H, dt), 5.34 (1H, t), 5.49 (2H, ddd), 6.27 (2H, dd) ppm. Its 13C-NMR spectrum has four signals – δ 26, 58, 127, 129 ppm. In the compound’s mass spectrum, the M+1 peak appears at m/z = 115. An M+2 peak, whose intensity is roughly one-third that of the M+1 peak, also appears. Suggest a structure for this compound.
A compound with molecular formula C3H8O produces a broad signal between 3200 and 3600 cm³¹ in its IR spectrum and produces two signals in its 13C NMR spectrum. Draw the structure of the compound. Draw Your Solution
What is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?
An unknown compound has the molecular formula C7H14O, and its 1H NMR and 13C NMR spectra are shown below. Determine the structure of the unknown compound and draw it below. Note that there are no peaks above 3 ppm in the 1H NMR, and the numbers present on the 1H NMR are the integration values for each set of peaks.
Compound A exhibits two signals in its 'H NMR spectrum at 2.64 and 3.69 ppm and the ratio of the absorbing signals is 2:3. Compound B exhibits two signals in its 'H NMR spectrum at 2.09 and 4.27 ppm and the ratio of the absorbing signals is 3:2. Which compound corresponds to CH;O,CCH,CH2CO,CH3 (dimethyl succinate) and which compound corresponds to CH;CO,CH2CH,O,CCH; (ethylene diacetate)?
A compound with molecular formula C3H8O produces a broad signal between 3200 and 3600 cm1 in its IR spectrum and produces two signals in its 1°C NMR spectrum. Draw the structure of the compound.
Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.
Compound A, with molecular formula C4H9Cl, shows two signals in its 13C NMR spectrum. Compound B, an isomer of compound A, shows foursignals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and B.
Each compound gives only one signal in its 1H-NMR spectrum. Propose a structural formula for each compound. Q.) C2H6O
There are four esters with molecular formula C4H8O2. How can they be distinguished by 1H NMR?

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