A carbonate mixture was titrated with 0.1100 M HCI. The sample weighing 850.0 mg took 21.00 mL to reach the phenolphthalein end point and an additional 14.00 mL to reach the methyl red end point. Calculate the weight percentage of the component/s.
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- 5. A 300.0 mg sample containing Na,CO3, NaHCO, and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 ml to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.5. A 300.0 mg sample containing Na,CO3, NaHCO3 and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 mL to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.An unknown sample containing mixed alkal (NaOH NaHCO or Na,CO) was analyzed using the double flask method, A 250 mg sample was dissolved in 250 m CO3 free water. A 20.0 mL aliquot of this sample required 11.3 ml. of 0.009125 M HCl solution to reach the phenolphthalein end point. Another 29.0 ml aliquot of the sample was bitrated to the bromocresol green endpoint using 31.1 ml of the standard acid. How many millimoles of the components are there in the original solid sample) 0-928 mmol No. 0.0103 mmol NaOH 0078 m N.CO Cannot be determined 012 mol NaC0, 197 minol NaHCO 129 mmol NaOH, 097ml Najco
- 0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point. What is the molar concentration required?0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point.A 0.15mL of phenolphthalein indicator was dropped to 10.00mL of an unknown acid. Then, 52.00mL from the 100mL of 10M NaOH Solution was placed in a 50mL burette. A titration experiment was done using the 10.15mL unknown acid with phenolphthalein indicator as analyte and the 52mL of NaOH as titrant. The solution turned pink when the final volume of the analyte was 10.68mL and the final reading in the burette was 51.47mL. What is the concentration of the unknown acid?
- A 250.0-mg sample of an organic weak acid was dissolved in an appropriate solvent and titrated with 0.0556 M NaOH, requiring 32.58 mL to reach the end point. Determine the compound’s equivalent weight.A solution of HCl was titrated against sodium carbonate. What is the titer for Trial 1 in the given data? T2 0.3562 0.3479 0.3042 Weight (g) Initial V (ml) 0.80 1.60 35.20 36.70 39.80 Final V (ml) Vol HCI used (ml) 35.10 N of HC (eq/L) 0.1954 0.1870 Average N of HCl (eq/L) ADirect titration: 10.90 ± 0.02 mL of an unknown KHP solution required 11.72 ± 0.02 mL of 0.1090 ± 0.0006 M NaOH to reach the end point. What is the concentration of KHP in the unknown solution reported with absolute uncertainty? If the unknown solution was prepared by dissolving 5.128 g of the unknown KHP (204.22 g/mol) in 100.00 mL of water, what is the weight percent of KHP in the sample?
- A sample containing the amino acid alanine, CH3CH(NH2)COOH, plus inert matter is analyzed by Kjeldahl method. A 2.00 g sample is digested, the ammonia is distilled and collected in 50.0 ml of 0.150 M H2SO4, and a volume of 9.0 ml of 0.100 M NaOH is required for back titration. Calculate the percent alanine in the sample.A 1.000 liter sample of sea water was evaporated to a small volume and treated with an excess of sodium tetraphenylboron. The precipitated tetraphenylboron was filtered and then redissolved in acetone. The analysis was completed by a Mohr titration that required 34.32 ml of 0.03875 M AGNO3. Calculate the parts per million of potassium in the sea water sample. K* + NaB(C,Hs)4 → KB(C,Hs)4(s) + Na* ; Ag* + KB(C,H5)4 > AgB(CgHs)4(6) + K*A pharmacist is conducting an analysis of 2.7 g sodium bicarbonate and titrated with 26.05 mL of 0.9987 N HCl. What is the potency or percent assay of sodium bicarbonate? Did it pass the USP requirement? ROUND-OFF TO 2 DECIMAL PLACES. Answer = _% Disposition (Passed or Failed) = _