A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate. 48.30 mass: g Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration. 3.576 [Na*] =| M Incorrect 2.763 [NO,] = M Incorrect 0.739 [Sr*] = M Incorrect 1.788 [F=] = M Incorrect
A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate. 48.30 mass: g Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration. 3.576 [Na*] =| M Incorrect 2.763 [NO,] = M Incorrect 0.739 [Sr*] = M Incorrect 1.788 [F=] = M Incorrect
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter17: Solubility And Complex-ion Equilibria
Section: Chapter Questions
Problem 17.100QP: A solution contains 0.00740 M calcium ion. A concentrated sodium fluoride solution is added dropwise...
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![A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the
< Feedback
mass of the resulting strontium fluoride precipitate.
The sodium ion concentration you
calculated is incorrect.
When calculating the Na+
concentration, you may have used the
48.30
mass:
volume of the original NaF solution.
Instead, use the total volume of both
Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for
solutions to calculate the concentration
the concentration.
in the final solution.
3.576
[Na*] =
M
Incorrect
2.763
[NO,] =
M
Incorrect
0.739
[Sr**] =
M
Incorrect
1.788
[F=] =
M
Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4cbada35-3122-4a6c-a25c-246bca0ae236%2F74d42509-6a39-4c94-bfeb-599449db7f5b%2Fsb6mzks_processed.png&w=3840&q=75)
Transcribed Image Text:A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the
< Feedback
mass of the resulting strontium fluoride precipitate.
The sodium ion concentration you
calculated is incorrect.
When calculating the Na+
concentration, you may have used the
48.30
mass:
volume of the original NaF solution.
Instead, use the total volume of both
Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for
solutions to calculate the concentration
the concentration.
in the final solution.
3.576
[Na*] =
M
Incorrect
2.763
[NO,] =
M
Incorrect
0.739
[Sr**] =
M
Incorrect
1.788
[F=] =
M
Incorrect
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