A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 mL aliquot was titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Anothr 20 mLaliquot was titrated to the BCG endpoint, using up 18.87 mL of titrant in the process.
A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 mL aliquot was titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Anothr 20 mLaliquot was titrated to the BCG endpoint, using up 18.87 mL of titrant in the process.
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.35QAP
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Please answer in simplest form, thank you so much 9
![A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 mL aliquot was
titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Anoth 20 mL aliquot was titrated to the BCG endpoint, using up 18.87
mL of titrant in the process.
The volume of titrant needed to neutralize NaOH is ( Select ]
v mL.
The volume of titrant needed to neutralize Na,CO, is [ Select ]
v mL.
The volume of titrant needed to neutralize NaHCO, is (Select]
v mL.
The percent weight of NaOH is [Select ]
く%。
The percent weight of Na,CO, is SelectJ
%.
The percent weight of NaHCO, is
Select]
MM: NaOH = 40 g/mol, NazCO; - 106 g/mol, NaHCO3 = 84 g/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5451c68a-411c-47a9-b876-a0c5ce58ef00%2F8bd96598-1246-4392-9a09-bd3f78bc203e%2Fagghng_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 15.00 g sample containing mixed alkali and other inert components was dissolved and diluted to 300 mL with water. A 20 mL aliquot was
titrated with 5.02 mL of 0.5352 M HCI to reach PHP endpoint. Anoth 20 mL aliquot was titrated to the BCG endpoint, using up 18.87
mL of titrant in the process.
The volume of titrant needed to neutralize NaOH is ( Select ]
v mL.
The volume of titrant needed to neutralize Na,CO, is [ Select ]
v mL.
The volume of titrant needed to neutralize NaHCO, is (Select]
v mL.
The percent weight of NaOH is [Select ]
く%。
The percent weight of Na,CO, is SelectJ
%.
The percent weight of NaHCO, is
Select]
MM: NaOH = 40 g/mol, NazCO; - 106 g/mol, NaHCO3 = 84 g/mol
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