A 12 V battery has an internal resistance of 3ohms. It is connected in series with a 6resistor and in series with a parallel pair of resistors, 4ohms and 12ohms. a) Sketch this circuit. b) Calculate the current and the voltage across the battery terminals.

A battery with E = 33 V and negligible internal resistance is connected to a voltage conductor as shown in the figure. R1=1 Ω R2=68 Ω a) How big will the voltage U2 be if no external load is connected? b) What will be the current between A and B if these connection points are short-circuited. c) How large will U2 be for a load with a resistance of 68 Ω connected between A and B? d) What is the power of the circuit if a load with a resistance of 68 ‌Ω is connected between A and B?

Four capacitors are arranged in the circuit shown in the figure. The capacitors have the values,C1=22.5 μF,C2=45.5 μF, ,C3=50.5 μF, and ,C4=40.5 μF, and the power supply is at voltage V=25.5 V.   What is the equivalent capacitance of the circuit? equivalent capacitance:     What is the charge on capacitor ?2?C2? charge on C2:     What is the potential difference across capacitor C3?     What is the potential energy stored in capacitor C4?

Three capacitors of capacitance 2µF,4µF and 6µF are connected in parallel in a circuit with a 3V battery. After the capacitors are done charging, how much charge has moved through the circuit? O a. 36 µC O b. 3.3 µC O c. 18µC O d. None of the above

Four capacitors are arranged in the circuit shown in the figure. The capacitors have the values C, = 25.5 µF, C = 45.5 µF, C3 = 50.5 µF, and C4 = 40.5 µF, and the power supply is at voltage V = 32.5 V. What is the equivalent capacitance of the circuit? equivalent capacitance: 13.24 What is the charge on capacitor C2 ? charge on C: 297.9 x10-6 What is the potential difference across capacitor C3? ас potential difference across C3: 3.28 V

A 10⁹-F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 6x10¹3 2; on a humid day, the resistance is 7 x 106 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? 4 On the dry day, it will take 4.159 × 10 seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.) On the humid day, it will take seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.)

A 10⁹-F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 6x10¹3 2; on a humid day, the resistance is 7 × 10 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.)

A capacitor with capacitance C = 5 μF is charged to a voltage V = 10V. It is then discharged through a resistor R = 2 MΩ. At what time after the start of the discharge process has the voltage across the capacitor fallen to 1V? Select one: a. 230 msecs b. 23 secs c. 10 secs d. 100 msecs

You have a circuit with a battery hooked up to 2 capacitors in Parallel. The battery has a voltage of 4.3 V. The capacitors have a value of C1 = 40.0 µF and C2 = 25.0 u F. While finding the actual voltage is very helpful, it's hard to use this as a prediction because not all batteries are the same. So one way to look at this is a percentage. Even if the voltage of the battery is different, the percentage of the voltage should be the same regardless. Find the percentage of the battery voltage that is across capacitor 1. To find percentages: • Find the voltage across the specific capacitor just like previously Divide this voltage by the voltage of the battery • Multiply your answer by 100 to turn it into a percent Your answer should include: 2 Decimal Places Correct SI Units Your Answer:

b. The voltage across the plates of a capacitor at any time t seconds is given by t V(t) = Ve¯RC where V, C and R are constants. Given V = 200 volts, C = 0.1 x 10-6 Farads and R = 4 x 105 ohms. Find i. The initial rate of change of voltage ii. The rate of change of voltage after 0.5 s.