A 100 ml solution of 0.1 M glycine at pH 1.72 was titrated with 2 M LIOH. The pH was monitored and the result were plotted as shown in the graph. The key points of the titration are designated as I to V. Identify the key point in the titration corresponding to the pH at which the carboxyl group is half deprotonated. 12 J130 10 9.60 (IV) 8 pH 6-597 4 234 2. 05 1.0 1.5 2.0 OH (equivalents) IV O l and IV Next
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- 80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pI. The solution is then titrated with 0.2M HCL to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCL needed to reach relevant pKa value and equivalence point(s)z Relevant pKa values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.Quinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =80mL of a 0.3M solution of hexapeptide Leu-His-Cys-Glu-Asn-Arg is adjusted to pH=pl. The solution is then titrated with 0.2M HCI to a final pH of 2.1. Sketch the titration curve, labelling the pH and volume axes. Indicate the volume of HCl needed to reach each relevant pKa value and equivalence point(s). Relevant pka values are: 2.1, 4.3, 6.0, 8.3, 9.8, and 12.5.
- if you have Quinoa Serving size -170 grams Carbohydrates – 109 grams calculate the DV % for these values?Draw dipeptide Arg-Thr at pH 6.0. Circle the six atoms that are restricted in one plane. Calculate its approximate pI assuming pKa for NH3+ is 10.0, pKa for COOH is 3.0, PKR for Arg is 12.0Potentiometric titration curve is given below, which is obtained during the potentiometric titration between strong base KOH (0.2 M) with strong acid HI, label the point in the curve from the following options. If more than one points are present than write as x, y(means separate by using comma) a)The point where pH is because of excess OH - ions. b) The point where pH is only because of HI in water. c)The point where [HI]= [I] in water. d)The point where pH=pka e) The point where all HI is neutralized. f) The point where pH corresponds to solution of [I- ] in water. 14 13 12 11 10 9 pH 6. TITIT TIT
- You have just used up the last of a 1.2 % m/m solution of agarose in water. You require another 100mls. How many grams of Agarose do you require? Note 1ml of water=1g What is the % w/v of a 100ml solution containing 5g of NaCl?You are trying to separate study Fibrinogen variants with a pl approximately 5.8. Which ion exchange resin would you use under the different conditions proposed? O Carboxymethyl at pH=2.8 O Alkylsulfonyl at pH=7.0 O DEAE at pH = 7.0 O Quaternary alkylammonium resin at pH=2.8 O DEAE and Carboxymethyl approaches could both work.100 g of a pretreated lignocellulose has a mass composition of 35% lignin, 40% cellulose, 15% xylan, and 10% "other." During hydrolysis 75% of the cellulose and 80% of the xylan are converted to products. What is the wt% composition of the insoluble solids following hydrolysis? Assume that the "other" fraction is unaffected by the hydrolysis.
- Tirofiban (C22H36N₂O5S MWt = 440.6) is present as tirofiban HCI monohydrate (C22H36N2O5S.HCI.H₂O MWt=495.1) at 0.281 mg/mL in a concentrated solution. A solution for infusion is prepared by extracting 50 mL from a 250 mL bag of 5% glucose solution and adding 50 mL of concentrated solution. Sofia who weighs weighs 87 kg requires a tirofiban dose of 0.1 mcg/kg/min for 12 to 24 hours. What would the infusion rate be (mL/h)? (Answer to 1 decimal place.) Answer:Tirofiban (C22H36N₂O5S MWt = 440.6) is present as tirofiban HCI monohydrate MWt=495.1) at 0.281 mg/mL in a concentrated solution. (C22H36N2O5S.HCI.H₂O A solution for infusion is prepared by extracting 50 mL from a 250 mL bag of 5% glucose s and adding 50 mL of concentrated solution. Sonya who weighs weighs 60 kg requires a tirofiban dose of 0.4 mcg/kg/min for 30 minute- What volume would remain after 30 minutes? Answer: 94.53 mL X The correct answer is: 236 mLGiven the titration curve of the hypothetical polyprotic acid X at 0.100 M concentration (pKa1=4.0, pKa2=8.0, pKa3=12.0) titrated with 0.600 M NaOH, identify the pH at point C, H, E, and M.