A 0.60 kg block rests on a frictionless horizontal surface, where it is attached to a massless spring whose k-value equals 18.5 N/m. Let x be the displacement, where x = 0 is the equilibrium position and x > 0 when the spring is stretched. The block is pushed, and the spring compressed, until x, = -4.00 cm. It then is released from rest and undergoes simple harmonic motion. (a) What is the block's maximum speed (in m/s) after it is released? 1.23 x Mechanical energy is conserved in this system, and the gravitational term remains unchanged (since all motion is horizontal). Write an expression for mechanical energy that includes the kinetic energy and the potential energy of the spring. Which term(s) can be ignored when the spring is compressed and the block at rest? Which term(s) can be ignored when the block is moving at its greatest speed? Use the remaining terms, and the given quantities, to solve for the maximum speed. m/s (b) How fast is the block moving (in m/s) when the spring is momentarily compressed by 2.20 cm (that is, when x = -2.20 cm)? 1.03 x Mechanical energy is conserved in this system, and the gravitational term remains unchanged (since all motion is horizontal), Write an expression for mechanical energy that includes the kinetic energy and the potential energy of the spring. Which term(s) can be ignored when the spring is compressed and the block at rest? Use the remaining terms, and the given quantities, to solve for the maximum speed. m/s (c) How fast is the block moving (in m/s) whenever the spring is extended by 2.20 cm (that is, when passing through x = +2.20 cm)? 1.03 x You are computing the speed of the block when it has the same distance from the midpoint as it had in part (b)-but on the other side. Does any term in the energy-conservation equation depend on the sign of the displacement, x? Could this insight help you answer this question once you have correctly solved part (b)? m/s (d) Find the magnitude of the displacement (in cm) at which the block moves with one-half of the maximum speed. [x] 3.46 cm

Classical Dynamics of Particles and Systems
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ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter12: Coupled Oscillations
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Problem 12.4P: Refer to the problem of the two coupled oscillators discussed in Section 12.2. Show that the total...
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A 0.60 kg block rests on a frictionless horizontal surface, where it is attached to a massless spring whose k-value equals 18.5 N/m.
Let x be the displacement, where x = 0 is the equilibrium position and x > 0 when the spring is stretched. The block is pushed, and
the spring compressed, until x, = -4.00 cm. It then is released from rest and undergoes simple harmonic motion.
(a) What is the block's maximum speed (in m/s) after it is released?
1.23
X
Mechanical energy is conserved in this system, and the gravitational term remains unchanged (since all motion is horizontal).
Write an expression for mechanical energy that includes the kinetic energy and the potential energy of the spring. Which
term(s) can be ignored when the spring is compressed and the block at rest? Which term(s) can be ignored when the block is
moving at its greatest speed? Use the remaining terms, and the given quantities, to solve for the maximum speed. m/s
(b) How fast is the block moving (in m/s) when the spring is momentarily compressed by 2.20 cm (that is, when x = -2.20 cm)?
1.03
Mechanical energy is conserved in this system, and the gravitational term remains unchanged (since all motion is horizontal).
Write an expression for mechanical energy that includes the kinetic energy and the potential energy of the spring. Which
term(s) can be ignored when the spring is compressed and the block at rest? Use the remaining terms, and the given
quantities, to solve for the maximum speed. m/s
(c) How fast is the block moving (in m/s) whenever the spring is extended by 2.20 cm (that is, when passing through
x= +2.20 cm)?
1.03
You are computing the speed of the block when it has the same distance from the midpoint as it had in part (b)-but on the
other side. Does any term in the energy-conservation equation depend on the sign of the displacement, x? Could this insight
help you answer this question once you have correctly solved part (b)? m/s
(d) Find the magnitude of the displacement (in cm) at which the block moves with one-half of the maximum speed.
1x1 = 3.46
cm
in i
Transcribed Image Text:A 0.60 kg block rests on a frictionless horizontal surface, where it is attached to a massless spring whose k-value equals 18.5 N/m. Let x be the displacement, where x = 0 is the equilibrium position and x > 0 when the spring is stretched. The block is pushed, and the spring compressed, until x, = -4.00 cm. It then is released from rest and undergoes simple harmonic motion. (a) What is the block's maximum speed (in m/s) after it is released? 1.23 X Mechanical energy is conserved in this system, and the gravitational term remains unchanged (since all motion is horizontal). Write an expression for mechanical energy that includes the kinetic energy and the potential energy of the spring. Which term(s) can be ignored when the spring is compressed and the block at rest? Which term(s) can be ignored when the block is moving at its greatest speed? Use the remaining terms, and the given quantities, to solve for the maximum speed. m/s (b) How fast is the block moving (in m/s) when the spring is momentarily compressed by 2.20 cm (that is, when x = -2.20 cm)? 1.03 Mechanical energy is conserved in this system, and the gravitational term remains unchanged (since all motion is horizontal). Write an expression for mechanical energy that includes the kinetic energy and the potential energy of the spring. Which term(s) can be ignored when the spring is compressed and the block at rest? Use the remaining terms, and the given quantities, to solve for the maximum speed. m/s (c) How fast is the block moving (in m/s) whenever the spring is extended by 2.20 cm (that is, when passing through x= +2.20 cm)? 1.03 You are computing the speed of the block when it has the same distance from the midpoint as it had in part (b)-but on the other side. Does any term in the energy-conservation equation depend on the sign of the displacement, x? Could this insight help you answer this question once you have correctly solved part (b)? m/s (d) Find the magnitude of the displacement (in cm) at which the block moves with one-half of the maximum speed. 1x1 = 3.46 cm in i
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