A 0.2602 g sample of an unknown monoprotic acid requires 12.23 mL of 0.1298 M NAOH solution to reach the end point. What is the molecular mass of the acid?

Q: A portion of aluminum metal (4.50 grams) is dissolved in 200 mL of Potassium hydroxide solution. How…

A: In this question, aluminium metal is dissolved in potassium hydroxide solution to form alum…

Q: A 7.96-g sample of a diprotic acid requires 136.0 mL of a 0.750 M NaOH solution for complete…

A: Given: Mass of sample = 7.96 g Volume = 136.0 mL Molarity of NaOH solution = 0.750 M

Q: Consider the reaction:2 K3PO4(aq) + 3 NiCl2(aq) -----> Ni3(PO4)2(s) + 6 KCl(aq)What volume of…

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Q: 12.What is the molarity of the resulting solution ? Of 60 ml of a 1.6 M nickel phosphate solution,…

A: Given: Molarity of nickel phosphate (M1) = 1.6 M Volume of nickel phosphate (V1) = 60 mL Final…

Q: Consider the following balanced equation: 2KMNO4(aq) + 10KI(aq) + 8H2SO4(aq) → 6K2SO4(aq) +…

A: 1)Given data in above Molarity  ( M1 ) or concentration of  KMnO4 = 0.205 M  Volume ( V1) of KMnO4 =…

Q: A 10.00 mL sample of 0.200 MHCl(aq) is diluted to a total volume of 100 mL. Calculate the molarity…

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Q: A 6.0 mL sample of a 52.5 % (m/v) acetic acid (HC2H3O2) solution is added to water to give a final…

A: Initial volume = 6mL  Mass by volume % = 52.5 %  Final volume = 47mL

Q: One way to remove lead from water is to add a source of iodide ion so that the lead will precipitate…

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Q: Consider the following precipitation reaction: 2Na3PO4(aq)+3CuCl2(aq)→ Cu3(PO4)2(s)+6NaCl(aq) What…

A: Solution stoichiometry involves the calculation of concentration of solutions in the given…

Q: What volume of 0.260 M Na2S solution is required to completely react with 40.00 ml of a 0.315 M…

A: We are authorized to answer one question at a time, since you have not mentioned which question you…

Q: A 25.00 mL aliquot of concentrated hydrochloric acid (11.7 M) is added to 175.00 mL of 3.25 M…

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Q: Consider the following precipitation reaction: 2Na3PO4(aq) + 3CuCl2(aq)➡️Cu3(PO4)2(s) + 6NaCl(aq)…

A: Molarity of a solution is defined as the number of moles of solute present in one litre of a…

Q: A mixture of hydrochloric acid and sulfuric acid is prepared so that it contains 0.635 M and 0.135 M…

A: Answer is explained below.

Q: If 200. mL of water is added to 300. mL of an aqueous solution that is 0.642 M in potassium sulfate,…

A:

Q: A 25.00 mL sample of sulfurous acid required 12.71 mL of 0.233 M potassium hydroxide for complete…

A: Given,  Volume of Sulfurous acid (VH2SO4) = 25.00 mL Volume of Potassium hydroxide (VKOH) = 12.71 mL…

Q: 3.* A 0.1936 g sample of an unknown monoprotic acid requires 15.56 mL of 0.1020 M NAOH solution to…

A:

Q: A 59.0 mL aliquot of a 1.30 M solution is diluted to a total volume of 248 mL. A 124 mL portion of…

A:

Q: Consider the following balanced equation: 2KMNO4(aq) + 10KI(aq) + 8H2SO«(aq) → 6K2S04(aq) +…

A: Volume of KI = 52.5 mL  1000 mL = 1 L  52.5 mL = 0.0525 L  Molarity of KI = 0.188 M Volume of KMnO4…

Q: What volume (mL) is required from a stock solution of 1.98m KNO3 to prepare a 750ml solution of 1.00…

A: We can solve the problem from the following formula : V 1 S 1 = V 2 S 2    Where : V1 = initial…

Q: A 21.47-mL sample of hydrochloric acid solution requires 35.00 mL of 0.109 M sodium hydroxide for…

A: Given :-  concentration of NaOH solution = 0.109 M  volume of NaOH solution = 35.00 mL  volume of…

Q: . Suppose 0.400 L of a solution of 0.0700 M nitric acid is added to 0.800 L of a solution of 0.0300…

A: Given : Concentration of Nitric acid i.e HNO3 in solution 1 = 0.0700 M Volume of solution 1 = 0.400…

Q: What volume of 0.165 M Na3PO4 solution is necessary to completely react with 88.6 mL of 0.106 M…

A: Given balanced chemical equation is 2Na3PO4 (aq) + 3CuCl2(aq) →Cu3(PO4)2(s) + 6 NaCl(aq)…

Q: If 52.00 ml of 0.500 M CaBr 2 solution is added to  128 ml of 0.320 M solution of KCl solution, what…

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Q: If a 57.0 mL sample of nitric acid is titrated with .375 M calcium hydroxide, and 23.0 mL are…

A: The reaction taking place is  2HNO3 + Ca(OH)2 ----> Ca(NO3)2 + 2H2O => for 2 moles of HNO3  we…

Q: 38 mL volume of 1.74 M Fe(NOa)a is mixed with 43 mL of 0.98M Fe(NOa solution. Calculate the molar…

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Q: What volume of a 0.143 M barium hydroxide solution is required to neutralize 23.3 mL of a 0.134 M…

A: The expression of dilution law is shown below: M1V1 =M2V2 where; M1 = molarity of known solution V1…

Q: 6 ml of concentrated HCl acid solution was diluted to 180 mL. Then 65 mL sample of the diluted…

A: The volume of the concentrated HCl solution taken = 6 mL The volume of the diluted HCl solution =…

Q: Consider the reaction: Li2S(aq) + Co(NO3)2(aq) →  2 LiNO3(aq) + CoS(s) What volume (in mL) of a…

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Q: In a beaker there are 100 mL of a 1M sodium hydroxide solution. If we add an HCl solution and both…

A: The total number of moles in reaction always remains constant. This can be represented with the…

Q: 16.0 mL of 0.018 M I- solution is mixed with another solution to a new total volume of 75.0 mL. What…

A: Given: Initial concentration of I- (M1) = 0.018 M Initial volume V1 = 16 mL Final volume V2 = 75.0…

Q: A solution is made by diluting 37 ml of a 10.25 mil/L standard solution to a volume of 2.40L. What…

A: Answer: The concentration of the resulting solution is 0.158 mol/L.

Q: A 6.50-g sample of a diprotic acid requires 137.5 mL of a 0.750 M NaOH solution for complete…

A: Given details, The balanced chemical equation, AH2 + 2NaOH ---> Na2A + 2H2O Mass of diprotic…

Q: An experiment was carried out as follows: 1.5766 g of an ammonium salt was placed in a beaker and 60…

A: The ratio of moles of solute to the volume of solution in liters is known as molarity.

Q: 90.0 mL of 0.30M MgCl2 is boiled down to a volume of 78.0 mL.  What is the concentration of the…

A: The initial volume of the given MgCl2  solution (V1) = 90.0 ml The initial concentration of the…

Q: A student needs to dilute a 0.41 M Pb(NO3)2 solution to make 59.0 mL of 0.10 M Pb(NO3)2. Set up the…

A: Number of moles of solute present in 1 liter of solution is known as molarity of the solution.

Q: A 23.85-mL sample of hydrochloric acid solution requires 30.00 mL of 0.112 M  sodium hydroxide for…

A: Acid is a compound which gives hydrogen ions in solution and base gives hydroxide ion in solution.

Q: If 0.500 mL of an 0.219 M NaCl solution is added to 100.0 mL of pure water.  what is the…

A: When we dilute a concentrated solution with pure water, the mole of solute remains constant in the…

Q: A 4.277-g sample of Alz(SO4)a was dissolved in distilled water to make a total volume of 250.0 mL of…

A: Answer :- Molar Concentration of sulfate SO42- ion in solution B = 0.015 M…

Q: How many mL of a 0.185 M aqueous solution of cobalt(Il) iodide, Col2, must be taken to obtain 20.5…

A: Cobalt (ll) Iodide ( CoI2 ) Molarity = 0.185 M = 0.185 mol/L Mass of CoI2 = 20.5 g   We know ;…

Q: What volume of 0.2456 M lead(II) nitrate solution would be required to reach the endpoint when…

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Q: Concentrated hydrochloric acid is about 12.1 M. What volume of concentrated HCl is required to…

A: Given,  Molarity of HCl before dilution = M1 = 12.1 M  Final volume = V2 = 5500 mL  Molarity of HCl…

Q: A 11.4 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid.If…

A: The reaction between hydroiodic acid and barium hydroxide is given as  2 HI + Ba(OH)2 ----> BaI2…

Q: An experiment was carried out as follows: 1.5766 g of an ammonium salt was placed in a beaker and 60…

A: Given % of NH4+ in the salt = 37.5 % Therefore 1.5766 g salt contain 1.5766 × (37.5/100) = 0.5912 g…

Q: What volume (in mL) of 5.00 M HCl must diluted to a final volume of 1.50 L to make a solution with a…

A: Given data, M1=5.00 MM2=0.470MV2=1.50L = 1500mL We have to calculate the initial volume in mL.

Q: A solution is prepared by adding 2.0 g of solid CaBr2 and 1.55g of NaBr to 100.ml of 0.15 M AlBr3.…

A: Given, A solution is prepared by adding 2.0 g of solid CaBr2 and 1.55g of NaBr to 100.ml of 0.15 M…

Q: Calculate the volume in L of 1.50 M sulfuric acid required to completely react with 25.00 ml of 2.25…

A:

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.