8.13 Refer to Figure P8.13. Determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 900 kN. 900 kN (net load) 1.52 m 1.83 mx 1.83 m Sand y= 15.7 kN/m³ Water table 1.22 m 3.05 m Sand Ysat 19.24 kN/m³ = Ysat 19.24 kN/m³ = eo= 0.68 - C=0.25 C₁ = 0.06 Preconsolidation pressure = 100 kN/m² Figure P8.13

8.13 Refer to Figure P8.13. Determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 900 kN. 900 kN (net load) 1.52 m 1.83 mx 1.83 m Sand y= 15.7 kN/m³ Water table 1.22 m 3.05 m Sand Ysat 19.24 kN/m³ = Ysat 19.24 kN/m³ = eo= 0.68 - C=0.25 C₁ = 0.06 Preconsolidation pressure = 100 kN/m² Figure P8.13

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.7P

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6.8 Refer to Figure P6.8. Using the procedure outlined in Section 6.8, determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 50 ton. [Use Eq. (6.28).] 4:5 ft 3 ft 50 ton (net load) 10 ft 5 ft x 5 ft Sand y=100 lb/ft! Sand Yat=122 lb/ft³ Groundwater table Ysat ⇒120 lb/ft³ = 0.7 C=0.25 -C, 0,06 Preconsolidation pressure = 2000 lb/ft² Figure P6.8
Solve Problem 7.8 using Eq. (7.29). Ignore the post-construction settlement. 7.8 Solve Problem 7.4 with Eq. (7.20). Ignore the correction factor for creep. For the unit weight of soil, use γ = 115 lb/ft3. 7.4 Figure 7.3 shows a foundation of 10 ft × 6.25 ft resting on a sand deposit. The net load per unit area at the level of the foundation, qo, is 3000 lb/ft2. For the sand, μs = 0.3, Es = 3200 lb/in.2, Df = 2.5 ft, and H = 32 ft. Assume that the foundation is rigid and determine the elastic settlement the foundation would undergo. Use Eqs. (7.4) and (7.12).
Problem 2. Determine the average (top, middle, and bottom) stress increase in the clay layer below the center of foundation due to foundation load of 50 tons. 50 ton (net load) Sand 100 Ib/ 4:5 t Groupdwater table 5 ft X 5 ft *Sand 122 lb/ft 3 ft A120 Ib/ft 0.7 C, = 0.25 10 ft 0,06 Preconsolidation pressure = 2000 lb/ft?
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