8-Define a scheme procedure that returns the total number of leaves of a tree For example, (count-leaves '((4 5 6) (3) () (1 2) )) returns 6 Then, manually trace the procedure with the given example.
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- Sum Lists' in Scheme; Write a function named sum-lists in Scheme that takes two lists as input and returns a new list containing the sum of each corresponding pair of elements. You may assume that the lists have the same length. For example, (sum-lists '(1 2 3 4) '(5 6 7 8)) should return '(6 8 10 12) (every-other '() '()) should return '()List ManipulationWrite the following functions on lists in Scheme. The semantics of the func-tions is described through examples.(1) (define rev (lambda (l) ...)) ...(rev ’(e b c d)) --> ’(d c b e)Note: This function reverses the components of a list. (2) (define maxx (lambda (l) ...))...(maxx ’(1 2 3)) --> 3Note: You are encouraged to use the reduce function- use scheme R5RS (no other language) for upvote - do not use do or set 1. Define the function (siftNum lst). This function should resolve to all the numbers in the list, lst. For example: (siftNum '(a 8 2 1 m l 90 p 2)) resolves to '(8 2 1 1 90 2)
- 1. Recursion & List processing Write a recursive function flatten that takes a list as an argument and returns the flat version of that list. For example, (flatten '(a (b c) d)) -> (a b c d) (flatten '(((a)) (b (c)) d)-> (a b c d)A- Declare a self-referential structure StudentNode for a linked list having one data field called GPA (float), and one pointer to StudentNode called next. B- Write a non-recursive function that prints all the GPAS that are less than or equal to 2 in your linked list starting from the head of the list. Example: If the list is 1.9->2->3.5->4->1.8, the function should print: 1.9->2->1.8. C- Write a recursive function that counts all the GPAS that are higher or equal to 3.5 in your linked list starting from the head of the list. Example: If the list is 1.9->2->3.5->4->1.8, the function should return 2.4-Write a Scheme procedure that takes a list and returns the sum of the number that are less than 6 in the list. For example, (sumeven '(1 (2 ( 5 () 6) 3 8) ) ) returns 11. Then, Manually trace your procedure with the provided example.
- Test the program using the following procedure (Use Linked List):⦁ Call enQueue(5)⦁ Call enQueue(2)⦁ Call enQueue(6)⦁ Call deQueue ()⦁ call deQueue()⦁ Call enQueue(3)⦁ Call enQueue(6)⦁ Call enQueue(3)⦁ Call Display() use C++ with DSA concepts6-Write a Scheme procedure that takes a list and returns the list created by switching successive elements in the list. For example (newlist ‘(a (b c ) (d) e f g)) returns ( (c b) a e (d) g f ) .Then, Manually trace your procedure with the provided example.1. Recursion & List processing Write an function maxlist that returns the maximum element in a simple list of numbers. (maxlist '(2 5 6 3)) -> 6
- *Needs to be done in scheme interleave* Implement function interleave in scheme, which expects as arguments two lists x and y, and returns asingle list obtained by choosing elements alternately, first from x and then from y. When either x or yruns out, interleave takes the remaining elements from the other list, so that the elements of the resultare exactly the elements of the two argument lists taken together. (interleave '(1 2 3) '(a b c)) -> (1 a 2 b 3 c) (interleave '(1 2 3) '(a b c d e f)) -> (1 a 2 b 3 c d e f) (interleave '(1 2 3 4 5 6) '(a b c)) -> (1 a 2 b 3 c 4 5 6)6. Write a function DOT-PRODUCT that takes two lists, each list has the same number of elements, and produces the dot product of the vectors that they represent. For example, (DOT-PRODUCT '(1.2 2.0 -0.2) '(0.0 2.3 5.0)) -> 3.6 Hint: The key for designing a lisp function is using recursion.List ConstructionWrite Scheme programs that generate the following lists as output using onlycons as the list building operator:(a) ’(b g (e f (b)))(b) The list L that contains three components such that the first componentis the number 2, the second component is the multiplication function(*), and the third component is ’d’, and that the following expression((car (cdr L)) (car L) 3) evaluates to 6.