#71 12. Use your answers for Questions 4 and 10 to calculate [SCN -] q, the equilbrium concentration of SCN-, for the Test Tube 3 reaction mixture described in Question 10. [FeSCN³¹] Initial Change Equilibrium [Fe³] Q1 answer (0.0010) -x (0.0000749) Q11 answer (0.00093) = [SCN -]q, Q4 answer - x 201 [SCN-] Q4 answer (0.00060) -x (0.0000749) Q12 answer (0.00053) +x x=Q10 answer (0.0000749) blano OH to Jm 0.S+ иоx M 900.0 to Jm 13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in Question 10? To answer this Question, you will need to plug your answers for Questions 10, 11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7. K. = [FeSCN 2+]/([Fe³+][SCN-]) Use the answers for questions 10, 11 and 12 to calculate Kc. Give the answer in two significant figures. azoqquê eau 838.0 ai,benila viriguotori

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#13 please
#7
12. Use your answers for Questions 4 and 10 to calculate [SCN-]q, the equilbrium
concentration of SCN-, for the Test Tube 3 reaction mixture described in Question 10.
[FeSCN³¹] 0.0
0100.0-SM
Answers
Initial
Change
Equilibrium
[Fe³+]
Q1 answer (0.0010)
-x (0.0000749)
Q11 answer (0.00093)
el 1 teenutim nollosen & eduT
019 bris bruongloe8" odf
#p=0.0000749
x=Q10 answer (0.0000749)
of nollasup
[SCN -] eq, Q4 answer - x
Jm De lo staisnop doinw eduTee hot stsb 1sbiano0
ermulov istof is evig od O. H to Jm 0. MOX OSC
13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in
Question 10? To answer this Question, you will need to plug your answers for Questions 10,
11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7.
K. = [FeSCN 2+]/([Fe³+][SCN-])
#11=0.00093
H12=0.00053
Use the answers for questions 10, 11 and 12 to calculate Kc. Give the answer in two significant
figures.
[SCN-]
Q4 answer (0.00060)
-x (0.0000749)
Q12 answer (0.00053)
+x
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[106] etsluolso of tuobnari
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ogne/13
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Transcribed Image Text:#7 12. Use your answers for Questions 4 and 10 to calculate [SCN-]q, the equilbrium concentration of SCN-, for the Test Tube 3 reaction mixture described in Question 10. [FeSCN³¹] 0.0 0100.0-SM Answers Initial Change Equilibrium [Fe³+] Q1 answer (0.0010) -x (0.0000749) Q11 answer (0.00093) el 1 teenutim nollosen & eduT 019 bris bruongloe8" odf #p=0.0000749 x=Q10 answer (0.0000749) of nollasup [SCN -] eq, Q4 answer - x Jm De lo staisnop doinw eduTee hot stsb 1sbiano0 ermulov istof is evig od O. H to Jm 0. MOX OSC 13. What is the calculated value of Kc for the Test Tube 3 reaction mixture described in Question 10? To answer this Question, you will need to plug your answers for Questions 10, 11, and 12 into the expression for Kc, which you identified if you correctly answered Question 7. K. = [FeSCN 2+]/([Fe³+][SCN-]) #11=0.00093 H12=0.00053 Use the answers for questions 10, 11 and 12 to calculate Kc. Give the answer in two significant figures. [SCN-] Q4 answer (0.00060) -x (0.0000749) Q12 answer (0.00053) +x otheanoo muhdilupe srl of belelen [408] eirit to sphechoads benuasem erit azoqquê nollsup2 asu 898.0 ei benida viriguotor [106] etsluolso of tuobnari be ( M2] lo sonschoedA MX A MOT] to note theorico mundillupe avode eldsl nollash 301 sill nix ont el owens erT GATO000 0-rro 888.0=X\A=M [408] noite tneonao mundliupe sitteistuolss of Of brist anoilaou not answers toy sau th 01 noliau ni badhoesb osutxim noltosen & eduT teeT or not to (200000.0) x- ogne/13 muhdilimpa ) ) ) ) ) ) ) ) )
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