7. Calculate AG° for the following galvanic cell Zn(s) | Zn²*(aq) || Fo2*(aq) IFe(s) given these reduction potentials: Zn2 (aq) + 2 e –→Zn(s) Fe2*(aq) + 2 → Fe(s) E° = -0.76 V E° = -0.45 V B) 59.8 kJ 8. For the galvanic cell that uses the reaction A) -59.8 kJ C) -29.8 kJ D) 29.8 kJ 2 Al(s) + 3 Zn2+(aq) → 2 Al3+(aq) + 3 Zn(s) the value of n in the relationship AG° = – NFE° is

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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.127QP
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7. Calculate AG° for the following galvanic cell Zn(s) | Zn²+(aq) I
Fe2*(aq) |Fe(s) given these reduction potentials:
Zn2*(aq) + 2 e –→Zn(s)
Fe2*(aq) + 2 e → Fe(s)
E° = -0.76 V
E° = -0.45 V
B) 59.8 kJ
8. For the galvanic cell that uses the reaction
A) -59.8 kJ
C) -29.8 kJ
D) 29.8 kJ
2 Al(s) + 3 Zn2+(aq) → 2 Al3+(aq) + 3 Zn(s)
the value of n in the relationship AG° = – 1FE° is
Transcribed Image Text:7. Calculate AG° for the following galvanic cell Zn(s) | Zn²+(aq) I Fe2*(aq) |Fe(s) given these reduction potentials: Zn2*(aq) + 2 e –→Zn(s) Fe2*(aq) + 2 e → Fe(s) E° = -0.76 V E° = -0.45 V B) 59.8 kJ 8. For the galvanic cell that uses the reaction A) -59.8 kJ C) -29.8 kJ D) 29.8 kJ 2 Al(s) + 3 Zn2+(aq) → 2 Al3+(aq) + 3 Zn(s) the value of n in the relationship AG° = – 1FE° is
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