5. The cable exerts a tension force T of magnitude 143.4 N on the rectangular plate at point A. Cal- culate the magnitude of the vector component of T normal to the plate. (Ignore the weight W.) (Ans: 53.90 N) 0.4 m B. 0.35 m 20° 15 kg G 0.45 m A W 0.7 m

P Steel cable Q2/ Find the displacement of point B. E, = 200GPa A, = 400mm2 L = 3m Answer B 45 8B = V1.3682 + 0.4182 30 Aluminum cable EAlu = 70GPA As = 400mm? L = 2m 20kN

A water supply pipeline crossing a wide river is to be supported by a flexible wire cable with an allowable tensile load of 30000 kg. The pipe weighs 60 kg per meter and has a total length of 100m. Determine the tension the Lowest point of the cable if the sag is to be 3m. a.) 25178.527 kg b.) 25718.725 kg c.) 25817.527 kg d.) None of the above e.) 25781.275 kg

iyi Q2: Two guy cables AB and AD are attached to the top of the transmission tower which have known tension forces. Determine the required tension T in 4 KN cable AC such that the net effect of the three cable 30 m tensions ( the resultant ot the system forces) is a downward force at point the magnitude of the resultant. 8KN A. Determine D. 20 m 50 m XIX IXI

Cable AB passes over the small ideal pulley Ćwithout a change in its tension. What length of cable CD is required for static equilibrium in the position shown? What is the tension Tin cable CD? T A 2.1' Answers: LCD= TCD= i i 44° с B 47 lb ft lb D

A bent rod ABC is supported by a pin and bracket at A and a cable CD. The weight of the bent rod is 15 N/m and is represented as distributed loads along segments AB and BC. B. C. 0.800 m D. 34.5 N at (0.750, 0, 0.400) m 12.00 N at (0.750, 0, 0.800) m 12.00 N at (0, 0, 0.400) m 34.5 N at (0, 0, 0.800) m y 15 N/m 1.500 m 1. Which of the following sets of reaction at A will complete the force diagram below? FAB and FBC represents the single resultant force associated with the distributed loads along segments AB and BC, respectively. 15 N/m 1.500 m, 0.800 m TCD D. FA represents a force reaction while CA represents a couple reaction at A. A. FAX, FAY, FAZ, CAY, CAz FAX, FAY, FAZ FAY, FAZ, CAX,CAY, CAZ FAX FAY, FAZ, CAX,CAY, CAZ 2. Which of the following gives the magnitude and point of application of the single resultant force FAB that is equivalent to the distributed load acting along segment AB? 0.800 m 0.600 m 0.600 m

LQ2. A 40-kg mass rests on the top of the folding workbench with a 50-kg mass with mass center G. Calculate the tension in cable FH and the x and y components of the force in the pin at E. 40 kg| |375 mm -450 mm- Ge D (B 225 mm F 900 mm E A 1200 mm

Example1: The block has a mass of 90 kg and it is supported by the cable system shown in figure. Determine the tensile force in cable DE. Solution: E.B.D. of ring at B F.B.D. of ring at D EB.D. of block TBD TAB TBC Три 40 30 45 TDE 40 Wolock = 90. 9.81 = 882.9 N TAB Block TBD

The tension acting on cable AB is 750 N. Calculate the moment about point O. Answer in N-m. 650 mm A 500 mm 30

2-111. Determine the angle between the two cables. *2-112. Determine the magnitude of the projection of the force F₁ along cable AC. Problems 2-111/112 2m 3 m F₂ = 40 N A Z F₁ = 70 N 3 m C 3 m 4 m 2 m B y